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  1. B = muo x n x i => i = B/muo n where muo = 4pi x 10^-7; n = no. of turns per unit length; B = magnetic field induction i = 0.30/(4pix10^-7x1200/0.75) => i = 149.2A

    2 Answers · Science & Mathematics · 03/04/2013

  2. B at the center of solenoid = muo x n x i = 4pi x 10^-7 x 1400 x 3.4 = 6x10^-3T Torque = BANi = 6x10^-3x1.2x10^-3x56x0.55 = 2.2x10^-4Nm

    2 Answers · Science & Mathematics · 18/03/2013

  3. .../m) mu0 - permeability of vacuum (air) = 4*pi*10^-7 H/m B = H*muo - magnetic induction .........(1) R - distance from antenna = 10^5 m r - radius of of...

    2 Answers · Science & Mathematics · 17/04/2007

  4. Hello Nicole, let us the expression B = (muo / 2 pi) * (I / d) Here B = 1.47*10^-8 T, d = 8.91*10...

    1 Answers · Science & Mathematics · 15/10/2012

  5. ...magnetic field induction at P2 is got by the formula B = (muo/4pi) (i/R) (sin@1+sin@2) muo = 4pi*10^--7 H/m; i = 0.556 A...

    1 Answers · Science & Mathematics · 09/12/2009

  6. ...would be more intense only along the axis of the solenoid. Its induction B = muo n i. Where muo = 4 pi *10^--7 H/m. n - the number of ...

    1 Answers · Science & Mathematics · 30/04/2010

  7. ... formula for parallel wires carrying current=(B*2*pi*r)/muo where B=magnitude of magnetic field =280 µT converting to...

    1 Answers · Science & Mathematics · 16/04/2015

  8. Use the equation: B=muo I/2piR so I=2piRB/muo

    2 Answers · Science & Mathematics · 17/06/2011

  9. ...field of induction intensity B, there is an energy density U = 1/(2*muo) * B^2 muo is the magnetical permitivity of the vacuum If ...

    2 Answers · Science & Mathematics · 19/06/2009

  10. ...wire), you can easily use the Ampere's theorem: B*2*Pi*d = muo I1 giving B= muo I1 / (2 Pi d) Then...

    4 Answers · Science & Mathematics · 15/08/2012

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