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...m) = PD(n) ⇒ PD(n) = PD(m) and thus

**mRn**⇒ nRm. Thus R is symmetric. And...1 Answers · Science & Mathematics · 18/11/2009

Rn represents the product of the matrix. See link: http://en.wikipedia.org/wiki/Matrix_%28mathematics%29 Good luck!

1 Answers · Science & Mathematics · 11/03/2011

Chuck Testa.

1 Answers · Science & Mathematics · 28/09/2011

No. 4R2 and 2R4 but 2 =/= 4.

2 Answers · Science & Mathematics · 05/05/2011

**mRn**: m = n^2^-1 rRs: r = s^2^-1 sRp: s = p^2^-1 r = (p^2^-1)^2^-1 C2 Answers · Science & Mathematics · 11/06/2008

NQ || MR ∠ 1 = ∠

**MRN**(alternate angles equal) ∠ 2 = ∠ NMR (corresponding ...4 Answers · Science & Mathematics · 30/11/2017

... is clear that the relation is reflexive (mRm always), symmetric (

**mRn**iff nRm), and transitive (**mRn**and nRo will always imply mRo...1 Answers · Science & Mathematics · 22/03/2014

Multiply numerator across and denominator across. We get mrst/nsmr. The m r and s cancels out. We are left with t/n, which is b.

3 Answers · Science & Mathematics · 01/03/2013

... = angle RNM and angle RNP = angle

**MRN**because when twp parallel lines (lines PR and MN) ...2 Answers · Science & Mathematics · 28/02/2008

I take it ℕ in this context refers to the set of natural numbers. To show a relation is an equivalence relation, we need to show that it is reflexive, symmetric, and transitive. Reflexivity: Clearly, for any natural number a, aRa...

1 Answers · Science & Mathematics · 18/09/2012

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