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  1. ...and zero. For any two positive integers m and n, mn > 0 and so mRn. For any two negative integers m and n, mn > 0 and so mRn...

    1 Answers · Science & Mathematics · 17/09/2019

  2. NQ || MR ∠ 1 = ∠ MRN (alternate angles equal) ∠ 2 = ∠ NMR (corresponding ...

    4 Answers · Science & Mathematics · 30/11/2017

  3. m = n^2 + 1...........(1) n = p^2 + 1..............(2) Substitute for n using (2) m = (p^2 + 1)^2 + 1 = p^4 + 2p^2 + 1 + 1 = p^4 + 2p^2 + 2

    2 Answers · Science & Mathematics · 22/12/2016

  4. ... is clear that the relation is reflexive (mRm always), symmetric (mRn iff nRm), and transitive (mRn and nRo will always imply mRo...

    1 Answers · Science & Mathematics · 22/03/2014

  5. I take it ℕ in this context refers to the set of natural numbers. To show a relation is an equivalence relation, we need to show that it is reflexive, symmetric, and transitive. Reflexivity: Clearly, for any natural number a, aRa...

    1 Answers · Science & Mathematics · 18/09/2012

  6. Multiply numerator across and denominator across. We get mrst/nsmr. The m r and s cancels out. We are left with t/n, which is b.

    3 Answers · Science & Mathematics · 01/03/2013

  7. for a you just sub the values in function 0.833M0 0.279M0 7.6 days just take the derivative for c then sub in 1 and 7

    1 Answers · Science & Mathematics · 19/01/2012

  8. ...reflexive: n-n=0 and 13|0 so nRn R is symmetric: If mRn then 13|(m-n), i.e., m-n = 13k for some integer k. Then n-m = -13k = 13(-k...

    1 Answers · Science & Mathematics · 07/05/2011

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