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...and zero. For any two positive integers m and n, mn > 0 and so

**mRn**. For any two negative integers m and n, mn > 0 and so**mRn**...1 Answers · Science & Mathematics · 17/09/2019

NQ || MR ∠ 1 = ∠

**MRN**(alternate angles equal) ∠ 2 = ∠ NMR (corresponding ...4 Answers · Science & Mathematics · 30/11/2017

m = n^2 + 1...........(1) n = p^2 + 1..............(2) Substitute for n using (2) m = (p^2 + 1)^2 + 1 = p^4 + 2p^2 + 1 + 1 = p^4 + 2p^2 + 2

2 Answers · Science & Mathematics · 22/12/2016

... is clear that the relation is reflexive (mRm always), symmetric (

**mRn**iff nRm), and transitive (**mRn**and nRo will always imply mRo...1 Answers · Science & Mathematics · 22/03/2014

I take it ℕ in this context refers to the set of natural numbers. To show a relation is an equivalence relation, we need to show that it is reflexive, symmetric, and transitive. Reflexivity: Clearly, for any natural number a, aRa...

1 Answers · Science & Mathematics · 18/09/2012

Multiply numerator across and denominator across. We get mrst/nsmr. The m r and s cancels out. We are left with t/n, which is b.

3 Answers · Science & Mathematics · 01/03/2013

for a you just sub the values in function 0.833M0 0.279M0 7.6 days just take the derivative for c then sub in 1 and 7

1 Answers · Science & Mathematics · 19/01/2012

Chuck Testa.

1 Answers · Science & Mathematics · 29/09/2011

...reflexive: n-n=0 and 13|0 so nRn R is symmetric: If

**mRn**then 13|(m-n), i.e., m-n = 13k for some integer k. Then n-m = -13k = 13(-k...1 Answers · Science & Mathematics · 07/05/2011

No. 4R2 and 2R4 but 2 =/= 4.

2 Answers · Science & Mathematics · 05/05/2011