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First you it to factor it... 3a^2-13a-10=0 <----- I prefer factoring using decomposition, so thats how I'll show you how to do it. First step is you want to find two numbers which same a sum of -13(middle term) and a product of -30(you...

4 Answers · Science & Mathematics · 31/01/2011

It is actually quite simple. sec(theta) = 1/cos(theta) tan(theta) = sin(theta)/cos(theta) multiply those together: [sin(theta)/(cos^2(theta)]*2 There you go. Hope that helps.

2 Answers · Science & Mathematics · 24/06/2012

when substituting you have to substitute the integration limits, too if u = 8y-5y^2+4y^3+1, then when y = 0, u = 1 when y = 1, u = 8 - 5 + 4 + 1 = 8 thus if the primitive is 3u^(1/3), the integral is 3*8^(1/3) - 3*1^(1/3) = 6 - 3 = 3 hope this helps

1 Answers · Science & Mathematics · 30/07/2014

C is "none". It is just a point on the side of a hill, not a max min or saddle. The others are right.

1 Answers · Science & Mathematics · 27/12/2010

Is it this book? http://www.mypearsonstore.com/bookstore/product.asp?isbn=0321593723&xid=PSED You can find it here 40 bucks cheaper... http://www.amazon.com/Precalculus-Concepts-Functions-Approach-Trigonometry/dp...

1 Answers · Science & Mathematics · 28/12/2008

Amazing, I thought I had this problem about a week ago, but I actually had this exact problem for homework about a year ago from my AP Calc BC class and asked the very same question on yahoo answers. So here's...

1 Answers · Science & Mathematics · 25/11/2010