mL HCl = ( MmL KOH* stoichiometric ratio) / M HCl =(1.00M * 25.0mL * 1 HCl/1KOH) / 0.45M =2.2
3 Answers · Science & Mathematics · 22/05/2007
Your description of the setup is not very clear, but the electrons are coming either from the copper, or the magnesium, being oxidized or reduced. For example the oxidation state of copper metal is zero, the oxidation state of copper in copper sulfate...
2 Answers · Science & Mathematics · 07/03/2007