when substituting you have to substitute the integration limits, too if u = 8y-5y^2+4y^3+1, then when y = 0, u = 1 when y = 1, u = 8 - 5 + 4 + 1 = 8 thus if the primitive is 3u^(1/3), the integral is 3*8^(1/3) - 3*1^(1/3) = 6 - 3 = 3 hope this helps
1 Answers · Science & Mathematics · 30/07/2014
The question is a fraud. Roth IRAs became possible in 1998. They have only been around for 16 year. The answer is that it is impossible for anyone to have invested in a Roth IRA for 20 years.
3 Answers · Business & Finance · 20/01/2014
I don't think they matter because many students use old textbooks or they just rent them. The professors aren't going to care about whether or not if the students have new textbooks. Can anyone answer my...
2 Answers · Education & Reference · 16/01/2014
I don't think that is a learning disabilities. But it may be it also could have something to do with other things that are going on in your life. Also maybe find a different way to studying and be careful not to over study also.
4 Answers · Education & Reference · 28/12/2013
...didn't get it right. There's no unit of measurement called "mml". Cysts are measured in millimeters, which...
1 Answers · Health · 16/12/2013