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1. ### How many moles of HCl (hydrochloric acid) are in 60.0 mLs of 0.400 M HCl?

Molarity = # Moles/ # Liters 0.400 M HCl = X Moles/.0600 Liters X Moles = .400 M HCl x .0600 Liters X Moles = 0.024 Moles

3 Answers · Science & Mathematics · 14/12/2013

2. ### Stock solution: 5.0 M NaCl. 300mL of 0.04 M are required. How many mLs of stock are needed?

Initial Volume X initial concentration = Final Volume X Final Concentration therefore: XL X 5.0M = 0.3L X 0.04M solve for X: X = (0.3L)(0.04M)/(5...

2 Answers · Science & Mathematics · 10/09/2007

3. ### How do you find concentration of HCl when given both mLs and concentration of NaOH? Please help I have been trying for hours!?

You have : ------------------ ( M HCl ) ( V HCl ) = ( M NaOH ) ( V NaOH ) M HCl = ( M NaOH ) ( V NaOH / V HCl ) M HCl = ( 0.02387M ) ( 42.10...

1 Answers · Science & Mathematics · 08/10/2015

4. ### How many mLs of a 5.89 M AgNO3 solution is needed to completely react with 25.0 mLs of a 3.67 M MgCl2 solution?

moles of MgCl2 ---> (3.67 mol/L) (0.0250 L) = 0.09175 mol For the equation, we will consume 2 moles of AgNO3 for every mole of MgCl2 consumed. Therefore: 0.09175 mol times 2 = 0.1835 moles of AgNO3...

2 Answers · Science & Mathematics · 05/05/2013

5. ### The following electrolytic reaction was run for 4 mins in 50 mLs to form iodine...?

More than one way to do this. Here is what I think is the easiest. pOH = 14 - pH pOH goes from 5.9 to 2.4 Work out initial, final values of [OH-] From the equation, for every two [OH...

1 Answers · Science & Mathematics · 14/09/2011

6. ### You have a solution that is 1.75 M H2SO4 (sulfuric acid). How many mLs of this acid do you need to prepare 100ml of 0.183 M H2SO4?

M1V1 = M2V2 (1.75 mol/L) (x) = (0.183 mol/L) (100 mL) x = 10.457 mL Round off as you see fit.

1 Answers · Science & Mathematics · 20/04/2014

7. ### How many grams of glucose do you need to add to 100 mLs of water to make a 1.0 mM solution of glucose?

You want 0.001 mol in 1 liter. because that is what means 1.0mM solution. So as 180g is 1 mole you need 180/1000 = 0.180g (180mg) for a liter. So devide that by 10 to get how much you need for 100ml. That is 18mg or 0.0180g. Hope that helps.

1 Answers · Science & Mathematics · 27/01/2010

8. ### Calculate the change in pH of the buffer when 10 mLs of 0.5 Molar Hydrochloric Acid is added to the buffer?

which buffer ?

1 Answers · Science & Mathematics · 05/03/2009

9. ### Plesae help me with this question The Ksp for Ag2CrO4 is 9.0 x 10-12. If 200 mLs of 0.0050 M AgNO3 is combined?

Qsp = [Ag+]²[CrO4+2] Qsp = [(0.0050 M)(200 ml) / (200 + 300 ml)]² [(0.0020 M)(300 ml) / (200 + 300 ml)] Qsp = 4.8e-9 Qsp > Ksp (precipitate forms)

1 Answers · Science & Mathematics · 05/03/2012

10. ### 16.93 g of LiI is dissolved in 100 mls of H2O and titrated with 1.63 M Ag2SO4 How many mLs of Ag2SO4 is needed?

Moles LiI = 16.93 g / 133.845 g/mol = 0.126 2 LiI + Ag2SO4 >> 2 AgI + Li2SO4 moles Ag2SO4 needed = 0.126 / 2 =0.0630 V = 0.0630 / 1.63 = 0.0387 L => 38.7 mL

1 Answers · Science & Mathematics · 05/10/2008