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  1. ... ADDITIVE, but assuming that they were, how many mLs of 18.0M H2SO4 must be ADDED to 100mL of H2O...

    3 Answers · Science & Mathematics · 18/08/2013

  2. ... 0.109 moles of NaClO4 in 1 L. With 380 mLs you can find the number of moles of that molecule. (0.109 moles...

    2 Answers · Science & Mathematics · 06/02/2013

  3. ...or even volume/weight? If it's volume/volume then the answer would be 27.3 mLs . You divide 508 by a hundred then multiply by 5.37. After you get that...

    1 Answers · Science & Mathematics · 20/01/2012

  4. let us calculate how many mLs we can make : MV/1000=X/Mw 0.3*V/1000=3.5/58 ...

    2 Answers · Science & Mathematics · 22/03/2011

  5. 17.0 ml. first you find your moles of SnCl2: .00618 then you do the 2 to 5 stoichiometric ratio of MnO4 to SnCl2: =.00247 moles Mno4 then you plug those moles into your molarity: .145M=.00247/?L =.017034L = 17...

    1 Answers · Science & Mathematics · 17/03/2010

  6. [H+] of 0.1M HCl = 0.1M [H+] of solution with pH = 4.0 = 10^-4 = 0.0001M Use dilution equation: M1V1 = M2V2 0.0001*40 = 0.1 *V2 V2 = (0.0001*40)/ 0.1 V2 = 0.04 Add 0.04mL of 0.1M...

    1 Answers · Science & Mathematics · 01/11/2011

  7. moles H2SO4 = 0.13 M x 0.0200 L=0.0026 H2SO4 + 2 NaOH = Na2SO4 + 2 H2O moles NaOH required = 0.0026 x 2 =0.0052 V = 0.0052/ 0.100 L=0.052 L => 52 .0 mL

    2 Answers · Science & Mathematics · 25/05/2010

  8. M1V1=M2V2 .737M*.035L=.827M*V2 (.737M*.035L)/.827M=V2 31.2mL=V2 there you go

    1 Answers · Science & Mathematics · 25/08/2012

  9. Use the titration formula for quickest results ml NaOH required = (1000 X 1.2 gKHP)/(0.5M X molar mass of KHP) the molar Mass of KHP = 204 .23 ml = 1000 X 1.2 /0.5 x 204.23 = 11.75 mls NaOH

    2 Answers · Science & Mathematics · 09/09/2011

  10. moles H2SO4 = 0.0200 L x 0.13 M=0.0026 the balanced equation is H2SO4 + 2 NaOH = Na2SO4 + 2 H2O the ratio between H2SO4 and NaOH is 1 : 2 moles NaOH required = 2 x...

    1 Answers · Science & Mathematics · 16/05/2010

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