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  1. You have : ------------------ ( M HCl ) ( V HCl ) = ( M NaOH ) ( V NaOH ) M HCl = ( M NaOH ) ( V NaOH / V HCl ) M HCl = ( 0.02387M ) ( 42.10...

    1 Answers · Science & Mathematics · 08/10/2015

  2. moles of MgCl2 ---> (3.67 mol/L) (0.0250 L) = 0.09175 mol For the equation, we will consume 2 moles of AgNO3 for every mole of MgCl2 consumed. Therefore: 0.09175 mol times 2 = 0.1835 moles of AgNO3...

    2 Answers · Science & Mathematics · 05/05/2013

  3. You want 0.001 mol in 1 liter. because that is what means 1.0mM solution. So as 180g is 1 mole you need 180/1000 = 0.180g (180mg) for a liter. So devide that by 10 to get how much you need for 100ml. That is 18mg or 0.0180g. Hope that helps.

    1 Answers · Science & Mathematics · 27/01/2010

  4. Qsp = [Ag+]²[CrO4+2] Qsp = [(0.0050 M)(200 ml) / (200 + 300 ml)]² [(0.0020 M)(300 ml) / (200 + 300 ml)] Qsp = 4.8e-9 Qsp > Ksp (precipitate forms)

    1 Answers · Science & Mathematics · 05/03/2012

  5. Moles LiI = 16.93 g / 133.845 g/mol = 0.126 2 LiI + Ag2SO4 >> 2 AgI + Li2SO4 moles Ag2SO4 needed = 0.126 / 2 =0.0630 V = 0.0630 / 1.63 = 0.0387 L => 38.7 mL

    1 Answers · Science & Mathematics · 05/10/2008

  6. For virtually all purposes yes. ml is the old way of measuring. This has been replaced by cc. They are almost identical.

    5 Answers · Science & Mathematics · 29/09/2006

  7. 20 ppm = 20 mg/L assuming it's on a mass basis and the solvent is water. 20 mg/L * 0.5 L = 10 mg

    1 Answers · Science & Mathematics · 12/03/2015

  8. The molar masses of LiI and Ag2SO4 are: 133.845 g/mol and 311.799 g/mol, respectively. Hence 16.93 g LiI is: (16.93 g)/(133.845 g/mol) = 0.12649 mol. Since 2 mole LiI will react with 1 mole of Ag2SO4: 2LiI...

    1 Answers · Science & Mathematics · 06/12/2008

  9. moles HCN = 25/27 g/mol=0.926 moles NaCN = 35/49 g/mol=0.714 [HCN]= 0.926/0.500 L=1.85 M [CN-]= 0.714/0.500=1.43 M pKa = 9.21 pH = 9.21 + log 1.43/1.85=9.10

    1 Answers · Science & Mathematics · 25/07/2009

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