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  1. Hello The spring force has to overcome the friction force: the friction force = mg*u the spring force = k *s mgu = ks s = mgu / k s = 0,14715 m --> answer Regards

    1 Answers · Science & Mathematics · 07/02/2011

  2. ...x - fk)*d =(F - mgcos@ - Nu_ k )*d =[F - mgcos@ - mgu _ k (cos@)]*d =[(70.0N) - (1.00kg)(9.80m/s^2)(cos50.0) - (1.00kg)(9.80m/s^2)(0.500...

    1 Answers · Science & Mathematics · 17/06/2012

  3. ...from 0 to 1) (1/√x) [f(x) - P(x)]² dx minimum => ∂I/∂α_ k = 2 ∫(from 0 to 1) (1/√x) [f(x) - P(x)] ∂P/∂α_ k = =2 ∫(from 0...

    1 Answers · Science & Mathematics · 13/03/2013

  4. ... after hitting the brake K (final) = 0 (the car stops) K (initial) = 1/2*m*v^2 - mgu * x = - 1/2 *m *v^2 ----> m will be canceled out. u = v^2 / (2*g*x...

    2 Answers · Science & Mathematics · 19/09/2011

  5. ... force times displacement. To find the force... F= mgu or. Force equals mass of puck, times gravitational constant ...

    2 Answers · Science & Mathematics · 19/02/2013

  6. ...) - F(friction) = F(applied) - mgu F(applied) = mgu = 5.0(9.8)(0.25) = 12.25 N i (b) Considering Conservation of Energy: K (initial) + W(applied) - W(friction) = K (final), K = 0...

    1 Answers · Science & Mathematics · 03/02/2014

  7. ...you will need to recalculate) potential energy U=mgh=176.4J at th bottom K =1/2mv^2, from here v=6.26 m/s vo^2=v^2-2a(x-xo) from here, a= -3.27 m/s F=N.u ma= mgu , u=a/g=.33 (coefficient) i am not 100% on the coefficient,everything else ...

    1 Answers · Science & Mathematics · 06/06/2009

  8. haha i had to add a boost or two to get up the first incline, but that was fun!

    2 Answers · Sports · 27/01/2009

  9. Considering I can't even make it up the first hill... it was pretty bad i'm sorry.

    3 Answers · Games & Recreation · 22/12/2008

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