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  1. ...78 m e) w = sqrt( k / m ) and w = V / A Rearranging we have A = sqrt( m / k )* V So if k doubles, A is reduced by the factor...

    2 Answers · Science & Mathematics · 08/09/2010

  2. ma = mg -kv^2 m dv/dt = mg - kv^2 m dv/dt = ( k / m ) [mg/ k - v ^2 ] Let k / m = a , mg/ k = b^2 dv/ (b^2- a ^2) = a dt. dv/dt = v * dv/ds since v = ds...

    1 Answers · Science & Mathematics · 12/01/2011

  3. ...ω = √( k / m ) and the equation of the motion is y = - Acos(√( k / m )*t) v = A *√( k / m )*sin(√( k / m )*t) a = A *( k / m )*cos(√( k / m )*t) and F = a * m F...

    2 Answers · Science & Mathematics · 20/09/2011

  4. ...epidermis of the leaf or stem of a plant, forming a slit of variable width that allows movement of...) ... and you've got K M V X left over...

    2 Answers · Education & Reference · 29/03/2012

  5. K = 1/2m * v ^2 therefore m =31, v =21 1/2m = 15.5kg, v ^2 = 441 K = 15.5*441 = 6835.5J

    2 Answers · Science & Mathematics · 22/11/2009

  6. a acceleratio b breadth c speed of light d distance e charge... force g acceleration due to gravity h height k constant l length m mass n number o p momentum q Q charge r radius s distance t time u initial velocity v final velocity w weight x unknown y unknown z

    5 Answers · Science & Mathematics · 19/06/2009

  7. ... = 1.616 m /s D) Θ = arccos[.05/0.2] = 75.52°; v = Vmax*sinΘ = 1.565 m /s E) amax = k * A / m = 13.07 m /s²

    1 Answers · Science & Mathematics · 21/04/2013

  8. .../ m )t) Perform the differentiation twice to obtain the acceleration... v = - A √( K / m )sin(√( K / m )t) a = -AK/ m * cos(√( K / m )t) If the block...

    1 Answers · Science & Mathematics · 03/12/2012

  9. a = dv/dt = mg/ k *(- k / m )*e^(kt/ m ) = -g*e^(kt/ m ) at t = 0 the rate of change a = -g = -9.8m/s^2 at t = 2 then a = -g*e^(2k/ m ) This means that the velocity is reducing since the value of a is negative

    1 Answers · Science & Mathematics · 24/03/2010

  10. Newton's 2nd law m g - m k v = m a If v is constant, a = 0 , then v = g/ k

    2 Answers · Science & Mathematics · 16/10/2009

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