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  1. ...and ω = √(k/m) V(max) = A√(k/m) V(max) / A = √(k/m) (V(max) / A)² = k/m k = (V(max) / A)²m k = (100 / 0.10)² * 5 k = 5 000 000...

    1 Answers · Science & Mathematics · 11/06/2017

  2. 1) V = A*√[k/m] 2) a = A*[k/m] Divide (1) by (2) to get V/a = √[m/k] Use this value in the formula for T: T = 2π√[m/k]

    1 Answers · Science & Mathematics · 09/12/2011

  3. ... a=(k^2)r(t^2) using F=ma F/m =(k^2)r(t^2) F=m(k^2)r(t^2) E= F x...m are constant so; 1/v is proportional to a v =s/t 1/v =t/s t/s proportional to a Substitute...

    1 Answers · Science & Mathematics · 29/03/2010

  4. ... directly proportional to d(mv)/dt. F = k d(mv)/dt F = m k d(v)/dt F = m k a k is just a proportionality constant so that the units of force, mass...

    2 Answers · Science & Mathematics · 11/09/2012

  5. ...^2 where V is max v. We solve for V and get... V = ± A √(k/m) = ± √( (k*x0^2+m*v0^2)/m )

    1 Answers · Science & Mathematics · 30/04/2009

  6. ... and C are increased m times. a new = k m^2 AB and v new = kk’m^3 ABC [v/a] new = m k’C = m [v/a] initial. Hence the proof. ================================

    3 Answers · Science & Mathematics · 16/02/2008

  7. to find the time t=2(pi)√(m/k) t=0.3410s amplitudde v=ω(√(a^2-y^2)) v(max)=aω ω=√(k/m) a=v(max)*√(m/k) a=0.01085 m acc(max) acc=a*ω^2 acc=a*v(k/m)^2 acc=a*(k/m) acc=3.69ms^2 hope this helps:D

    2 Answers · Science & Mathematics · 22/11/2011

  8. ...kA² = ½mv² v = √(kA²/m) = A√(k/m) v/A = √(k/m), therefore: ω = √(k/m) T = 2π/ω = 2π√(m/k) = 2π√(0.1kg/200N/m) = 0.14 s

    1 Answers · Science & Mathematics · 26/03/2016

  9. ...to find 1/4 of the time of one period. Let: V = maximum speed = 1.85 m/s A = maximum acceleration... / K V² / A² = M / K (V / A)² = M / K...

    1 Answers · Science & Mathematics · 18/11/2012

  10. (a) T = 2π√(m / k) where T = period = ? m = mass = 0.382 kg k = spring constant = 1.28 N/m so T = 2π√(0.382 / 1.28/k) T = 3.43 s (b) The amplitude is just the distance it was pulled...

    2 Answers · Science & Mathematics · 08/09/2012

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