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...and since: k = a <=>

**a**=**k**m = a+b <=> b =**m**-**k**we have that span{u ,**v**} is a subset of span {x,**v**} and vice versa. Therefore span {x ,**v**...2 Answers · Science & Mathematics · 04/01/2013

...the sequence of functions (f_n) is uniformly bounded by k in

**V**. So, any**M**≥**k**satisfies in**V**the condition required by the theorem. ...2 Answers · Science & Mathematics · 17/12/2009

...of a and b, it follows that c^m = (

**a**^**k**)^m = (a^**m**)^**k**= e^k = e and c^n = (b^l)^n = (b^n)^l = e^l = e Let's take the u and**v**from above theorem and make the following two ...2 Answers · Science & Mathematics · 26/07/2009

...there is

**a****k**> 0 such that y_n is in**V**_m for all n >= k. Case 1: k <... a contradiction since y_m is in K_**m**=**K**\(**V**_m). Case 2: m <...2 Answers · Science & Mathematics · 16/10/2010

...1)b = b^(-1) = 1/b, = -b, the additive inverse of b. Moreover, k X (m X b) = k X b^m = (b^

**m**)^**k**= b^(km) = (km) X b, so scalar multiplication is associative. And k X (a + b) = k X ab = (ab...1 Answers · Science & Mathematics · 04/03/2009

...y + z >= 44. Computing the number of (p,

**v**,w,x,y) such that 5p + 4v + 3w + 2x + y <...1) = m yield a solution of kb_0 + (k-1)b_1 +...+b_(k-1) =**m**-**k**by setting b_0 = a_0 -1, b_1 = a_1 and so on, except...6 Answers · Science & Mathematics · 17/01/2011

...in G degree(

**v**) <= M for every**v**in G |E| = |blue| + |red| + |green| |blue| = k...| M = (|R| + |S| + |T|)**M**=**k**M |E| <= k M |E...3 Answers · Science & Mathematics · 10/04/2007

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