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**m**going to assume you mean orthogonal...case, you are seeking**a**vector (**a**, b, c) such that (**a**, b, c) ***v**= 0. Since**v**= (1, 2, 1) in...b, -**a**-2b), or u = ai + bj + (-**a**-2b)**k**, where**a**and b are real ...1 Answers · Science & Mathematics · 17/07/2012

...motion is described by : deflection = s = A .sin(ωt) where ω = √( k / m ), A = amplitude and t = time. The velocity is: v = ds/dt = A .ω.cos(ωt) so A .ω = A .√( k / m ) = 5.4 at...

1 Answers · Science & Mathematics · 30/04/2011

a =kt² ; so v = ∫ a .dt = ⅓. k .t³ + C₁and s = ∫ v .dt = k .t⁴/12 + C₁.t + C₂ ; ... v = t³/27 +10 which at t=2 gives v = 10.3 m /s

2 Answers · Science & Mathematics · 01/09/2013

Part 1 Find time period (T) from the formula T = 2*pi*(

**M**/**k**)^0.5 Then use T = 2*pi / ! Part 2 At equilibrium**v**=**A*** ! From here calculate**A**but this**A**is w.r.t origin and...2 Answers · Science & Mathematics · 17/07/2011

mv'+kv=mg

**v**'+(**k**/**m**)**v**=g Let**k**/**m**=**a**Use (**k**/**m**=**a**) to get the integrating...t=0, v0=mg/**k**+C C=v0-mg/**k v**=mg/**k**+(v0-mg/**k**)e^((**k**/**m**)t)) From there you can integrate one more...1 Answers · Science & Mathematics · 31/07/2009

... + g*

**m**/**k**)*(**m**/**k**) = -(**V*****m**/**k**+ g*(**m**/**k**)^2) So: x(t) =**A**-(**V*****m**/**k**+ g*(**m**/**k**)^2)*exp(-**k***t/**m**) - g***m***t/**k**If we take x = 0 as the initial position...1 Answers · Science & Mathematics · 19/10/2008

Without any info. as to what "

**v**","w", and "**k**" represent no one can know the answer.1 Answers · Science & Mathematics · 24/09/2011

Relevant Formula: V (max)= A √( k / m ) ----------------------------------------------------------------- V (max)= 0.50m/s , K =15 N/ m , and m =1.3kg...

2 Answers · Science & Mathematics · 09/03/2013

...by basic fomulas of shm, angular frequency W = square root of

**k**/**m**(both**k**,**m**inside the root) = 10.52 rad/s max speed**V**=omega***A**=10.52*0.12=1.2624**m**/s mag of max acceleration = omega*omega***A**= 10.52*10.52...1 Answers · Science & Mathematics · 16/05/2012

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**a**) At the top of the loop, the gravitational force must be equal to the centrifugal force, i.e., mv^2/R = mg**v**= sqrt(gR) = 3.13**m**/s (b) Frictional F = mu N = (0.35)(2 kg)(9.8**m**/s^2...3 Answers · Science & Mathematics · 20/07/2013