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  1. LHS = 1 - [ (sin²x tanx ) / (tanx + 1) ] - [ cos²x / (tanx + 1) ] = [( tanx...

    2 Answers · Science & Mathematics · 08/12/2017

  2. LHS= cos(x-pi/2)/sin(x-pi/2)= [cos(x)*0+sin(x)*1]/ [sin(x)*0-cos(x)*1]= sin(x)/[-cos(x)]= -tan(x)= RHS.

    4 Answers · Science & Mathematics · 12/01/2018

  3. ...(θ/2)) = |cos(θ/2)| = cos(θ/2) ..... since cos(θ/2) > 0 for 0 ≤ θ ≤ π = LHS

    3 Answers · Science & Mathematics · 03/12/2017

  4. .../cosA 1 - sin²A = cos²A Starting with the LHS we have : ∴ LHS = [(secA + tanA) /(secA - tanA...

    4 Answers · Science & Mathematics · 20/11/2017

  5. LHS = (secA-cosA)/(cosA-sinA) = (1 - cos²A...

    2 Answers · Science & Mathematics · 19/11/2017

  6. LHS: csc θ - cot θ = 1/sin θ - cos θ/sin θ = (1 - cos θ)/sin θ Multiply...

    1 Answers · Science & Mathematics · 08/11/2017

  7. ... - cos2A = 2sin(B + A)sin(A - B) LHS = [2cos(A + B)cos(A - B)] /[2sin(B + A)sin...

    1 Answers · Science & Mathematics · 21/10/2017

  8. LHS= cos(4x)+cos(6x)-cos(2x)-1= cos(4x)+cos(6x)-2cos^2(x)= 2cos(5x)cos(x)-2cos^2(x)= 2cos(x)[cos(5x)-cos(x)]= 2cos(x)[-2sin(3x)sin(2x)]= -4cos(x)sin(3x)sin(2x)= RHS

    2 Answers · Science & Mathematics · 21/10/2017

  9. 5/6x=-2/18 multiply LHS by 3/3 15/18x = -2/18 multiply both sides by 18 15x = -2 divide both ...

    6 Answers · Science & Mathematics · 16/10/2017

  10. ... + sin B) = (sin B - sin A) / (cos A + cos B) LHS = (cosA - cosB)/(sinA + sinB) {multiply by conjugate of...

    4 Answers · Science & Mathematics · 14/10/2017

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