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The answer is d - on the

**LHS**you have 2 hydrogen atoms but on the left there's 4.1 Answers · Science & Mathematics · 29/09/2018

**LHS**= (cos 2x - cos x) / (cos x - 1) = [ 2cos^2(x) - 1 - cos(x)]/[cos(x) - 1...3 Answers · Science & Mathematics · 06/06/2018

**LHS**= -(**LHS**) --->**LHS**+ (**LHS**) = 0 2(**LHS**) = 0 or**LHS**= 05 Answers · Science & Mathematics · 02/05/2018

...equation is not an identity, if that is what you mean. Let y = π/2.

**LHS**= csc(y) = csc(π/2) = 1 RHS = cot(y)sec(y) = cot(π/2)sec(π/2) The...6 Answers · Science & Mathematics · 21/04/2018

...want that 2^3 * 5 * 7* x = n² For this, all powers on the

**LHS**bust be multiples of 2 [why?]. So you need an extra 2 to make 2^4...4 Answers · Science & Mathematics · 10/03/2018

... does not hold because 1 ≠ 2 ≠ 3 ≠ etc. for n >= 2.

**LHS**= [n(n+1)/2][1/n] = (n+1)/2 RHS = [n!]^(1/n) Therefore [(n+1...2 Answers · Science & Mathematics · 15/02/2018

... is P(k + 1): 5^(k + 1) + 6^(k + 1) < 7^(k + 1)

**LHS**= 5^(k + 1) + 6^(k + 1) = 5·5^k + 6·6^k = 5(5^k + 6^k) + 6^k RHS = 7...4 Answers · Science & Mathematics · 05/03/2018

... to ensure no root is lost. (because sinx between -1 and 1, ditto for the

**LHS**quadratic, and after solving for x: 1.29 < x <...3 Answers · Science & Mathematics · 28/01/2018

Your expression is an identity and not an equation

**LHS**= (x + y)^-2 = 1/(x + y)^2 = 1/[ x(1 + y/x)]^2 = 1/x^2(1 + y/x)^2 = x^-2(1 + y/x)^-2 = RHS1 Answers · Science & Mathematics · 17/01/2018

...0; inequality becomes x(x + 1)² + y(y + 1)² ≥ 8xy; expand

**LHS**: x³ + y³ + 2x² + 2y² + x + y = x³ + y³...2 Answers · Science & Mathematics · 17/01/2018