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  1. Here's the first as an example of the layout: LHS = cosθcotθ = cosθ * cosθ/sinθ ... because cotθ = 1/tanθ = cos^2θ / sinθ = (1 - sin...

    1 Answers · Science & Mathematics · 28/01/2015

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    3 Answers · Science & Mathematics · 11/08/2014

  3. 9) LHS = cos ( x + y - y ) LHS = cos...LHS = sin x - ( sin y / cos y )*cos x LHS = (sin x cos y - sin y cos x ) / cos...2 x cos^2 y - sin^2 x sin^2 y ) LHS = ( sin^2 x - sin^2 x sin^2 y - sin...

    2 Answers · Science & Mathematics · 18/04/2013

  4. sin x + sin 2x = sin x + 2 sin x cos x = sin x (1 + 2 cos x) 1 + cos x + cos 2x = 1 + cos x + (2cos^2 x - 1) = cos x + 2 cos^2 x = cos x (1 + 2 cos x) ∴ (sin x + sin 2x)/(1 + cos x + cos 2x) = sin x(1 + 2 cos x)/[cos x(1 + 2 cos x)] = sin x/cos x = tan x. Note that the double-angle identities for sine and cosine were...

    3 Answers · Science & Mathematics · 25/05/2012

  5. Expand the RHS -2[sin(x/2)cos(y/2)+sin(y/2)cos(x/2)][sin(x/2)cos(y/2)-sin(y/2)cos(x/2)]=-2[sin^2(x/2cos^2(y/2)-sin^2(y/2)cos^2(x/2)] using difference of two squares change the cos^2(y/2)=1-sin^2(y/2) and cos^2(x/2)=(1-sin^2x/2) to obtain -2(sin^2(x/2)-sin^2(y/2)) convert the sin^2(x/2) and sin^2(y/2) to the double...

    1 Answers · Science & Mathematics · 20/06/2013

  6. ... LHS = sin⁴ x + cos⁴ x = ( sin² x )² + ( cos²...

    1 Answers · Science & Mathematics · 08/08/2010

  7. Method - 1 ...................... On LHS, writing tan as ( sin / cos ), and taking...tan (45°-x) = (1-t) / (1+t). Hence, on the LHS ... Numerator = [ (1+t) / (1-t) ] - [ (1-t...

    3 Answers · Science & Mathematics · 23/04/2010

  8. LHS = sin(x) + sin(x + 14π/3) + sin(x - 8π/3) = sin(x) + sin(x + 2π/3) + sin(x - 2π...

    3 Answers · Science & Mathematics · 05/03/2013

  9. 1. LHS = sinx cosx tanx - 1 = sinx cosx (sinx/cosx) - 1 = sin²x - 1 = -(1 - sin²x) = - cos 2x = RHS Hence proved 2. LHS = sin²x(cos²x/sin²x + 1) = sin²x[(cos²x + sin²x)/sin²...

    2 Answers · Science & Mathematics · 11/05/2010

  10. LHS = (1 + cos(x)) / (1 - cos(x)) = ((1 + cos(x))/cos(x)) / ((1-cos(x))/cos(x)) = (sec(x) + 1) / (sec(x) - 1) = (1 + sec(x)) / (sec(x) - 1) = RHS LHS = (sin(x) + tan(x)) / (cos(x) + 1) = (sin(x) + sin(x)/cos(x)) / (cos(x) + 1) = sin(x...

    1 Answers · Science & Mathematics · 03/06/2008

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