x^2 = y ... y is a variable, not a constant like 4 ... different rules apply a^y = b^x a = b^(x/y) until you know a number value for b and y (which has become a root) we don 't know if the answer is pos, neg, or imaginary.

2 Answers · Education & Reference · 30/03/2020

...the given symbols or do it from the very bottom & let x be in the

**LHS**& show using case work that it will always exist in the RHS, therefore...1 Answers · Education & Reference · 11/07/2017

... you :) ___________ n + 6(n-2) = -5 + 6n 1) Multiply (n-2) by 6 on

**LHS**n + 6n - 12 = -5 + 6n 7n - 12 = -5 + 6n 2) Add 12 to both sides 7n...3 Answers · Education & Reference · 25/08/2015

...the equation is very straightforward. 15(100) = X (Simplify the

**LHS**) 1500 = X Thus the car is 1500 lbs.2 Answers · Education & Reference · 13/03/2015

... sides by 5a 5ab/5a = (d + 5ac) / 5a '5a' on the

**LHS**cancels down . b = (d + 5ac) / 5a Done!!3 Answers · Education & Reference · 20/01/2015

We can factorise the

**LHS**expression to give (2cosx + 1)(cosx + 2)=0. Therefore, we can say 2cosx + 1...2 Answers · Education & Reference · 04/11/2014

(Subtracting 9 from both sides) -x^2 +9 - 9= - 9 (On

**LHS**the +9 and - 9 cancel each other out) -x^2 = - 9 (Divide both sides...4 Answers · Education & Reference · 26/10/2014

4x/(2x+3) > 2 subtract 2 from both sides, so 4x/(2x+3)-2>0 simplify (4x-2(2x+3))/(2x+3)>0, -6/(2x+3)>0 for the

**LHS**to be positive the denominator must be negative, so 2x+3<0, i.e. x<-3/21 Answers · Education & Reference · 03/10/2014

...you can only alter the denominator, but no matter how large you take x, the value of the

**LHS**will never reach zero. Unless this is a Limit problem? ...4 Answers · Education & Reference · 29/09/2014

Solution: 4s+5-3/4s +5+5=0 (bringing all terms on

**LHS**) 4s-(3/4s+3/4s)+5+5=0 4s-3/2s+10=0 5s/2+10=0 s=-41 Answers · Education & Reference · 23/09/2014