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  1. I am going to assume that 70K and 30K are forces expressed in unknown units. Let 70K act at A, 70K act at B R = 70K + 30K = 100K Take...

    1 Answers · Science & Mathematics · 17/12/2010

  2. LHS=cos5x-cos3x =-2sin4x.sinx =-4sin2x.cos2x.sinx =-8sin^2x.cosx(2cos^2x-1) =-8sin^2x(2cos^3x...

    1 Answers · Science & Mathematics · 09/07/2011

  3. LHS: F=m.a =kg. m/s2 =ML/T2 RHS: rho=kg/m3 g =m/s2 V=m3 Multiplying these, F=kg.m/s2 =ML/T2 Thus, RHS=LHS Hence the proof!

    1 Answers · Science & Mathematics · 03/09/2013

  4. Put the LHS all in cartesian form and collect common terms, then convert to polar form. ...e. (80-j80). This remove the j term from the denominator. Second part of LHS is converted using Re^(jθ)=Rcosθ+jRsin...

    2 Answers · Science & Mathematics · 25/04/2013

  5. Put the whole left side (LHS) into sines and cosines: tan^2 = sin^2 / cos^2 csc^2 = sin^-2 sec...sin^2 * (sin^2 * cos^2)) / (cos^2 *(cos^2 + sin^2)) cancel the cos^2 and rearrange: LHS = (sin^4) / (cos^2 + sin^2) sin^2 + cos^2 = 1, so LHS = sin^4 Now...

    1 Answers · Science & Mathematics · 23/11/2011

  6. for continuity, the LHS limit and RHS limit must be equal... Here, put the value of "x"...

    1 Answers · Science & Mathematics · 31/10/2013

  7. First separate the variables (t to the LHS, s to the RHS) 4dt = t·√(t² -4) ds → 4/[t·√(t²...

    1 Answers · Science & Mathematics · 05/03/2007

  8. Simplify LHS to: 2{cos(2x)+sin(2x)} = 2√2{(1/√2)cos(2x)+(1/√2)sin(2x)} =2√2(cos(2x-(π/4))) Solve.

    1 Answers · Science & Mathematics · 20/04/2013

  9. Assuming that the left hand support (LHS) is pinned then take moments about the LHS RHS...

    2 Answers · Science & Mathematics · 13/09/2009

  10. ...39;s first find the intersection point of the tangent lines: subtract the LHS of the second eqn from that of the first eqn. 3y + 13 + 3y + 1 = 0 6y...

    1 Answers · Science & Mathematics · 17/02/2012

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