sin3y/siny = sin(y+2y) / siny = ( sinycos2y + cosysin2y) / siny Using sin2y = 2sinycosy = [ sinycos2y + 2siny(cosy)^2 ] / siny = siny[ cos2y + 2(cosy)^2 ] / siny = cos2y + 2(cosy)^2 = cos2y + 2(cosy)^2 - 1 + 1 Using cos2y = 2(cosy)^2 - 1 = cos2y + cos2y + 1 = 2cos2y + 1
3 Answers · Science & Mathematics · 28/12/2008
Note that the side in the middle is shared by both triangles. This means that that side is congruent for both triangles as well. Since we have two sides congruent already and the side shaded is congruent, all 3...
2 Answers · Science & Mathematics · 25/04/2010
the trick is to multiply the numerator&denominator of the right side by (1-sinθ) to get 1-sin(θ)^2 that way you can convert to cos(θ)^2 then you break the fraction into two look here: http://i279.photobucket.com/albums/kk124/firelilee/img475.jpg
4 Answers · Science & Mathematics · 03/03/2009
sec=1/sin cosec=1/cos cot=1/tan=cos/sin sina/1/sina+cosa/sina-1+cosa/1/cosa+cosa/sina+1= 1. sin^2a+sina/cosa+cosa/sina-1+cos^2a+1=1 (sin^2a+cos^2a)+(sin^2a+cos^2a)/coasina-1=1 1+(cos^2a+sin^2a-1=1 1-1+(sin^2a+cos^2a=1sin^2a+cos^2a=1.
2 Answers · Science & Mathematics · 26/05/2008
why should one be penalized if you showing the two sides are equal ? Typically we start with the more complicated side and it usually is on left.
3 Answers · Science & Mathematics · 11/01/2014
Your first equation, using parentheses, is better. Yahoo!Answers doesn't lend itself to vertical fractions! Use the Pythagorean Identity sin²θ = 1-cos²θ...
1 Answers · Science & Mathematics · 14/10/2016
If you mean cos(2A) then (1+cos2A)/(cos2A) = Tan2A/tanA 1+cos2A=tan2A*cos2A/tanA 1+cos2A=sin2A/tanA 1+cos2A=(2*sinA*cosA)/(sinA/cosA) 1...
1 Answers · Science & Mathematics · 07/05/2008
take log(base a) both sides
3 Answers · Science & Mathematics · 04/08/2012
http://www.openaspdf.com/files/735057/WolframAlpha--_1_cos_x____tan_x___2____1_sin_x____1_sin_x____Result__2014_03_06_0259.pdf
2 Answers · Science & Mathematics · 11/03/2014
( 0! + 0! + 0! + 0! ) ! = 24 ( (0! +0!) ^ (0! +0!) ) ! = 24
1 Answers · Science & Mathematics · 08/07/2008
