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related to: LHS

1. ### Derive the following equation. cosh (x+y) = cosh x cosh y + sinh x + sinh y?

LHS = cosh ( x + y ) = [e^(x + y) + e^(- x - y)]/2 RHS = cosh x cosh y + sinh x sinh y =[(e^x + e^-x)/2][(e^y + e^-y)/2] + [(e^x - e^-x)/2][(e^y - e^-y)/2] = (1/4)[e^(x + y) + e^(x - y) + e^(- x + y) + e^(- x - y)] 　　+ (1/4)[e^(x + y) - e^(x - y) - e^(- x + y) + e^(- x - y)]　 = (1/2)e^(x + y) + (1/2)e^(- x - y) = [e^(x + y) + e^(- x - y)]/2 so , LHS = RHS

2 Answers · Science & Mathematics · 14/05/2014

2. ### TRIG IDENTITIES: How to prove that (- 6 - 6sinx) / 5cosx = (- 6cosx)/(5(1 - sinx))?

LHS = -6/5 * (1 + sin(x))/cos(x) * (1 - sin(x))/(1 - sin(x)) [Multiply the top...

3 Answers · Science & Mathematics · 09/12/2011

3. ### prove the following identity?

LHS = [ ( 1 - cos 2x ) + sin 2x ] / [ ( 1 + cos 2x ) + sin 2x ] . . . .= [ ( 2 sin² x...

2 Answers · Science & Mathematics · 12/12/2010

4. ### Proof: trig Identities?

LHS = [2sin²(x)cos(x)-2sin^4(x)cos(x)-cos(x)] / [cos(x)(1-sin²(x...

1 Answers · Science & Mathematics · 22/05/2009

5. ### Trig identities question?

LHS = tan²A - sin²A sin²A/cos²A - sin²A...

1 Answers · Science & Mathematics · 15/01/2014

6. ### Prove: (sinx + tanx) / (cscx + cotx) = sinxtanx?

* LHS * Since tan(x) = sin(x)/cos(x), csc(x) = 1/sin(x) and cot(x) = cos(x)/sin...

3 Answers · Science & Mathematics · 11/06/2011

7. ### Solve calculus identity?

LHS : (sin 2x) / (1 - cos 2x) = (2sinxcosx) / (1-(1-2sin²x))....Make double angle...

2 Answers · Science & Mathematics · 16/06/2013

8. ### Math Question? Trig Identity?

LHS (sinx + tanx) / (1 + cosx) >> multiply sinx by (cosx/cosx) = [sinx(cosx/cosx) + tanx...

2 Answers · Science & Mathematics · 04/02/2013

9. ### Solve the Identity (cotx)/(1-tanx)+(tanx)/(1-cotx) = 1+tanx+cotx?

LHS = cot(x) / (1-tan(x)) + tan(x) / (1 - cot(x)) = (1/tan(x)) / (1 - tan(x)) + tan(x...

4 Answers · Science & Mathematics · 13/12/2007