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  1. 1. LHS: taking first component: cosA / (1- ...) and so we are left with sinA + cosA, LHS = RHS as required. 2. LHS tan^2(θ) + cot...

    2 Answers · Science & Mathematics · 09/07/2012

  2. You have a hint. The integral has something to do with a trigonometric function. So, let's work from there Let x = a * sin(t), then dx would equal a * cos(t) * dt dx / sqrt(a^2 - x^2) => a * cos(t) * dt / sqrt(a^2 - a^2 * sin(t)^2) => a * cos(t) * dt / (sqrt(a^2 * (1 - sin(t)^2)) => a * cos(t) * dt...

    2 Answers · Science & Mathematics · 13/12/2011

  3. (27^x + 3) cannot "simplify to" 69(3^(2x) + 1). It is true that 27^x+3=3{3^(2x)+1}

    1 Answers · Science & Mathematics · 24/06/2011

  4. Here's what I got from this: Your first trig identity, which says [A] sin^2(x) + cos^2(x) = 1, can be rewritten as [B] cos^2(x) = 1 - sin^2(x), so my first step would be: [1 - sin^2(x)] / [1 + cot^2(x)] [cos^2(x)] / [1 + cot^2(x...

    2 Answers · Science & Mathematics · 07/05/2011

  5. LHS = sec^2 x - cosec^2 x 1/cos^2 x - 1/sin^2 x = RHS tan^2x - cot^2x...1 - [1/sin^2x - 1] = 1/cos^2x - 1/sin^2x - 1 + 1 = 1/cos^2x - 1/sin^2x so LHS = RHS b) LHS sec x + tan x = 1/cos x + sinx /cos x = (1 + sin...

    3 Answers · Science & Mathematics · 20/09/2007

  6. [tan(x)-cot(x)]/[tan(x)+cot(x)] = sin^2(x)-cos^2(x) Expand to expressions of sine and cosine. [sin(x)/cos(x) - cos(x)/sin(x)] / [sin(x)/cos(x) + cos(x)/sin(x)] = sin^2(x)-cos^2(x) Find the common (denominator) of both the Denominator and the Numerator. For both, it will be sin(x)cos...

    1 Answers · Science & Mathematics · 10/05/2011

  7. Hint: the top is a^4 - b^4 = [ a ² + b ² ] [ a ² - b ² ] for appropriate a & b

    1 Answers · Science & Mathematics · 08/05/2011

  8. From the identity sin^2(x) + cos^2(x) = 1, we have 1 + tan^2(x) = sec^2(x), by dividing by cos^2(x). tan^2(x)/ (1 + tan^2(x) ) = tan^2(x) / sec^2(x) = tan^2(x) * cos^2(x) = (sin^2(x)/cos^2(x)) * cos^2(x) = sin^2(x) Anytime you see tan^2, cot^2, sec^2, or csc^2, recall the identity sin^2(x) + cos^2(x) = 1, and divide by either sin^2(x...

    1 Answers · Science & Mathematics · 07/05/2011

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