Yahoo Web Search

  1. Sort by

  1. LHS(left hand-side)=csc(π-θ)=1/sin(π-θ) =1/cos(θ)=secθ=RHS sin(π-θ)=cos(θ) because sin(π-θ)=sin(π)sinθ-cos(π)cosθ =0×sinθ-(-cosθ)=0+cosθ=cosθ

    2 Answers · Education & Reference · 07/04/2009

  2. LHS = 1 + cos (2x) - cos² x = 1 + 2 cos² x - 1 - cos² x ... [using the double angle formula cos (2u) = 2 cos² u - 1] = cos² x = RHS

    1 Answers · Education & Reference · 12/12/2012

  3. LHS: 2 csc 2u = 2 / (sin 2u) = 2 / (2 sin u cos u) = 1 / (sin u cos u) = (1/sin u) * (1/cos u) = sec u csc u = RHS

    1 Answers · Education & Reference · 26/01/2014

  4. LHS log (x-3) + log x can be written as log (x-3) multiplied with log x oh i just got confused.. need to help yew but.......... lol

    4 Answers · Education & Reference · 14/04/2012

  5. LHS = 5x - 5/8 RHS = 4x + 13/4 5x-5/8 = 4x + 13/4 5x - 4x = 13/4 + 5/8 x = 13/4 + 5/8 x = 26/8 + 5/8 x = 31/8

    1 Answers · Education & Reference · 12/09/2013

  6. 1) LHS = tanx sinx + cosx = (sinx/cosx) sinx + cosx = (sin² x / cosx) + cos x = [(1...

    1 Answers · Education & Reference · 27/04/2010

  7. LHS: 4^(x-1)=(2^2)^(x-1)=2^(2x-2) RHS: 32^4=(2^5)^4=2^20 Therefore 20=2x-2 x=11

    1 Answers · Education & Reference · 24/01/2014

  8. LHS = sin x - 2 sin x cos x taking sin x common , we get sin x ( 1 - 2 cos x ) = RHS Good luck !

    1 Answers · Education & Reference · 03/08/2012

  9. By FOIL, it is 1 - sin^2 x which by the Pythagorean identity is cos^2 x

    1 Answers · Education & Reference · 21/05/2013

  10.            tan²x • (csc²x – 1) = 1    sin²x • [ (1 ⁄ sin²x)  –  1 ] ⁄ cos²x = 1        (1 – sin²x) ⁄ cos²x = 1  ...  use identity: 1 – sin²x = cos²x...

    1 Answers · Education & Reference · 21/05/2013

  1. Ad
    related to LHS
  1. Try asking your question on Yahoo Answers