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  1. LHS: csc θ - cot θ = 1/sin θ - cos θ/sin θ = (1 - cos θ)/sin θ Multiply...

    1 Answers · Science & Mathematics · 08/11/2017

  2. ... - cos2A = 2sin(B + A)sin(A - B) LHS = [2cos(A + B)cos(A - B)] /[2sin(B + A)sin...

    1 Answers · Science & Mathematics · 21/10/2017

  3. LHS= cos(4x)+cos(6x)-cos(2x)-1= cos(4x)+cos(6x)-2cos^2(x)= 2cos(5x)cos(x)-2cos^2(x)= 2cos(x)[cos(5x)-cos(x)]= 2cos(x)[-2sin(3x)sin(2x)]= -4cos(x)sin(3x)sin(2x)= RHS

    2 Answers · Science & Mathematics · 21/10/2017

  4. 5/6x=-2/18 multiply LHS by 3/3 15/18x = -2/18 multiply both sides by 18 15x = -2 divide both ...

    6 Answers · Science & Mathematics · 16/10/2017

  5. ... + sin B) = (sin B - sin A) / (cos A + cos B) LHS = (cosA - cosB)/(sinA + sinB) {multiply by conjugate of...

    4 Answers · Science & Mathematics · 14/10/2017

  6. ...)cos(2A) and 2−2cos(4A) = 4sin²(2A) ∴ LHS = 4sin²(2A)(1−cos(2A)) = 4(4sin²Acos²A)(...

    1 Answers · Science & Mathematics · 03/10/2017

  7. ...go sweetheart :) 4ln(x) - ln(x²) = 1 Apply the log laws on the LHS : ln(x^4) - ln(x²) = 1 ln(x²) = 1 Now take the exponential on...

    2 Answers · Science & Mathematics · 29/09/2017

  8. ...to show that the x components are the same on both sides LHS = (v₁∂/∂x+v₂∂/∂y+v₃∂/∂z)(v₁,v₂...

    3 Answers · Science & Mathematics · 16/09/2017

  9. ...now, collect like terms) = (a + b)x + (2a + b). So, since the 1 on the LHS has no x coefficient, 1 = 2a + b & 0 = a + b. So b= -a, so a = 1...

    2 Answers · Science & Mathematics · 13/09/2017

  10. .... What happens when x = y ?????? Substitute y = x : LHS = x + x = 2x RHS = 2√(x*x) = 2√(x²) = 2x Since LHS...

    2 Answers · Science & Mathematics · 10/09/2017

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