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1. ### Verify this trigonometric identity. sinx/(1+cos⁡x) + (1+cosx)/sinx = 2cscx?

LHS= sinx/(1+cos x) + (1+cosx)/sinx = [sin^2x + (1+cos x)^2] / sinx(1+cosx...

1 Answers · Education & Reference · 12/11/2011

2. ### Math Homework Help Please!?

LHS =s(s-a) + (s-b)(s-c) = ((a+b+c)/2) ((a+b+c)/2)-a) + ((a+b+c)/2)-b) ((a+b+c)/2...

1 Answers · Education & Reference · 17/02/2010

3. ### How do I do this problem? Trig help?

LHS: -> tan^2x - sin^2x -> (sin^2x/cos^2x) - sin^2x (tanx = sinx/costx) -> [sin...

2 Answers · Education & Reference · 24/03/2010

4. ### I need help proving the following trigonometric function:?

* LHS * Note that tan(A) = sin(A)/cos(A) and sec(A...

3 Answers · Education & Reference · 09/07/2011

5. ### I need help proving the following trigonometric function:?

* LHS * Note that tan(A) = sin(A)/cos(A) and sec(A...

3 Answers · Education & Reference · 09/07/2011

6. ### How do you solve this? 10 easy point?

* LHS * Factoring... (cos²(x) - sin²(x))/(cos(x)(cos(x) + sin...

1 Answers · Education & Reference · 11/06/2011

7. ### Pre Calc HELP?! THANKS!<3?

LHS = sin^5 x cos² x = sinx (sin² x)² cos² x = sin x (1 - cos² x)² cos² x = sin x (1 - 2cos² x + cos^4 x) cos² x = sinx (cos² x - 2 cos^4 x + cos^6 x) = RHS

1 Answers · Education & Reference · 20/01/2013

8. ### tanx/cscx=secx-cosx ?

LHS = tan x / cscx = [sinx / cosx] / [1 / sinx] = [sinx / cosx] * [sinx / 1] = sin²...

1 Answers · Education & Reference · 05/06/2012

9. ### how do you prove these trigonometry question?

LHS =sinθ(1/sinθ-sinθ) =1-sin^2θ --- since sin^2θ+cos^2θ=1 =cos^2θ =RHS LHS =sinθ(cosθ+1)/cosθ(1+cosθ) =sinθ/cosθ =tanθ =RHS

2 Answers · Education & Reference · 25/05/2012