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...two vectors. Does it make sense? Yes, it's another vector.

**k**(a-b) x (a x**c**) is the cross product of two vectors. Does it make sense? ...1 Answers · Science & Mathematics · 15/07/2016

Using the binomial theorem (sqrt(2)-1)^

**k**=**C**sqrt(2) - D where**C**and D ...1) = Csqrt(2) - D then (sqrt(2)-1)^**k**= -(**C**+D)sqrt(2) + (2C+D) If...2 Answers · Science & Mathematics · 30/10/2008

They lie on a straight line if the gradient of AB equals the gradient of BC So (4-

**k**)/4 = (1-3k-4)/2 Maybe you can take it from there !2 Answers · Science & Mathematics · 01/04/2010

You didn't kill the f off when you put the squared sign in and also there's no reason for the minus sign of x-1 to randomly become a plus... Thus y=7(-1/6(x-1))^2+1 is what you're after. So y=7(1/36(x-1)(x-1)) and tbh I wouldn't much bother with multiplying that out '...

1 Answers · Science & Mathematics · 06/03/2012

QE : 1x² + (-

**k**)x + (2k-10) = 0 ∴ a = 1, b = -**k**,**c**= 2k - 10 .......... (1) For equal roots, discriminant Δ = b²...1 Answers · Science & Mathematics · 09/04/2011

Yes it is the same . Just like y = mx+b is the same as y = b+mx We just usually write the vertical shift last, since it's the last computation. Hoping this helps!

4 Answers · Science & Mathematics · 01/09/2011

Those two interpretations are equivalent, and they are both correct. Let me explain something with a simpler example. Begin with the graph of this equation: y = f(x) Transform it to this: y = -2f(x) This typically is...

2 Answers · Science & Mathematics · 23/10/2016

... the binomial probability formula: P(X =

**k**) =**C**(n,**k**) * p^**k*** q^(n-**k**) n : number of ...5,3) * 0.08^3 * 0.92^2 = ... P(X=4) =**C**(5,4) * 0.08^4 * 0.92^1 = ... P(X=5...2 Answers · Science & Mathematics · 12/01/2017

In the first one you need to evaluate the equation for x = 0 to find the y-intercept. y = a(0-p)^2 + q y = ap^2 + q this will be the y -intercept You can do the same in the second, but it will be "

**c**", yes.1 Answers · Science & Mathematics · 11/02/2008

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