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  1. Kelvin degrees are the same "size" as Celsius degrees. The scale is simply shifted 273.15 degrees. K = C+273.15 Do the arithmetic, and there's your answer.

    1 Answers · Education & Reference · 02/11/2010

  2. b^2 - 4ac > 0 a = 4 b = -k c = 9 (-k)^2 - 4 * 4 * 9 > 0 k^2 - 144 > 0 (k + 12)(k - 12) > 0 k < -12 k > 12

    1 Answers · Education & Reference · 01/11/2014

  3. ... provinces of Canada. Wealthy industrialist K.C. Irving and his family built an industrial conglomerate in the city...

    1 Answers · Education & Reference · 05/06/2012

  4. ...x | N, M, R) = ( M C x ) * ( (N - M) C (K - x) ) / ( N C K ) If you have n objects and...

    2 Answers · Education & Reference · 04/12/2007

  5. ...equal roots as a solution. In x^2-kx +(k+8), a = +1. b= -k, and c = (k+8) Therefore from b^2 - 4ac = 0, (-k)^2 -4(1)(k+8) = 0 k^2-4k-32 = 0...

    1 Answers · Education & Reference · 25/10/2012

  6. ... [C]= .6M [D]=.6M we know K=[C][D]/[A}[B]=.6*.6/(.2*.2)= 9

    1 Answers · Education & Reference · 23/10/2013

  7. ... described below, where c is any integer: k = 2 (-6c^2 + c + 5) k = -12c^2 + 10c + 8 k = -12c^2 + 14c + 6 k = 2c (11 - 6c) For example, when c...

    2 Answers · Education & Reference · 19/02/2014

  8. ...coefficient. P(n,k) is k-permutations of {1,2,...,n}. P(n,k) = C(n,k)*k!.

    2 Answers · Education & Reference · 06/01/2011

  9. => f(x) = x^2 - kx + 5 a = 1 b = -k c = 5 b^2 - 4ac = 0 => only one zero. y^2 - 4*1*5 = 0 y^2 = 20 y = ±2√5

    1 Answers · Education & Reference · 21/03/2016

  10. ...101.3 kPa) = 0.95755 atm For temperature, convert to Kelvins: K = °C + 273 K = 5 + 273 K = 278 The volume is in the right...

    3 Answers · Education & Reference · 11/12/2012

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