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  1. ...temperature is decreased , then K will increase from its original K(c) [ when temperature is normal ] so By Le-chatelier's principle , K...

    1 Answers · Science & Mathematics · 09/07/2016

  2. V1 / T1 = V2 / T2 Substitute and solve. Don't forgot to convert deg C to K for gas problems.

    2 Answers · Science & Mathematics · 13/07/2016

  3. ...0 K = -273.15°C and 273.15 K = 0°C; that is, K = °C + 273.15 You can think of both temperature scales having the same...

    3 Answers · Science & Mathematics · 02/07/2016

  4. ... the concentrations in equilibrium state satisfy the relation: K = [C]/ ( [A]∙[B] ) Equilibrium constant and free energy change ...

    3 Answers · Science & Mathematics · 23/06/2016

  5. The range when converted from degree celsius to Kelvin is 263 to 278 K. Add up 273 and (-10) and 273 with 5. U have probably understood the formula if not please comment me.Thank you

    1 Answers · Science & Mathematics · 16/05/2016

  6. 0.79 J/(g*K) = 790 J/(kg*C)

    3 Answers · Science & Mathematics · 25/04/2016

  7. ...251 L) / ((3.33 x 10^-3 mol) x (62.36367 L torr/K mol)) = 886 K (c) P = nRT / V = (0.0466 mol) x (0.08205746 L atm/K...

    1 Answers · Science & Mathematics · 15/04/2016

  8. ... / dS .. T = (92380 J) / (198.3 J/K) = ___ K = __ °C ******* you get to finish

    1 Answers · Science & Mathematics · 10/04/2016

  9. After the reaction, C2H5OH and CH3COOH remained 1/3 mol of each, that meant the amounts of alcohol and acid used in this reaction are 2/3 mol of each. The equilibrium constant: kc = [CH3COOC2H5][ H2,O...

    1 Answers · Science & Mathematics · 28/03/2016

  10. K = °C + 273.15. Hence, °C = K - 273.15 = 4 - 273.15 = -269.15° C

    2 Answers · Science & Mathematics · 17/03/2016

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