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...(+) + e ---> Na E = -2.71V K (+) + e ---> K E = -2.93V Rb(+) + e ---> Rb E = -2.93V Cs (+) + e ---> Cs E = -2.92V From the above values...

...intercept), you use the equation b^2-4ac=0. You plug in 20 for b, 25 for a, and k for c . You get: 625-80k=0. Then you can add 80k to both sides to...

...induction - first take n = 0 then we have sum (i = 0) = C ( k -1, k -1) = 1 = C ( k , k ) so the result is correct... k )! k ]/[ k !(m+1)!] =(m+1+ k )!/[ k !(m+1)!] = C (m+1+ k , k ) so the formula also holds for n = m+1 ...

... that, you don't care about absolute zero. A temperature difference in K or C is the same measurement. (Ditto for Fahrenheit and ...

1) E = 1 – ( c / k ) … assuming that’s what you mean Multiplying both sides by... (√5) But neither of those is simpler than the original c ) 4√b / [(√3) – b] Rationalizing the denominator by multiplying...

dT/dt = k ( C - T) ∫ dT / ( C - T) = ∫ k dt - ln...(t)= Ae^(-kt) + C T(0)= Ae^(- k (0)) + C = 100 A + C = 100 C = -A + 100 T...

The x-intercept occurs when y = 0 - k / c = log_a(d(x - h)) d(x - h) = a^(- k / c ) x = [a^(- k / c )]/d + h

... 6C2 = 15 ways.    In general, there are (m+ k -1) C ( k -1) ways. So if n > (m+ k -1) C ( k -1)  then at least 2 ...