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  1. Supposing the sucrose does not hydrolyze: (25.7 g C12H22O11) / (342.2965 g C12H22O11/mol) / (1 L) x (0.082057366 L atm/K mol) x (20 + 273) K = 1.81 atm 

    1 Answers · Science & Mathematics · 27/05/2020

  2. ... (150 kPa x  1 atm / 101.325 kPa))(6.85 L) / (35.0°C + 273.15)K = (1 atm)V₂/(273.15 k) V₂ = (150 kPa x 1 atm / 101.325 ...

    1 Answers · Science & Mathematics · 28/05/2020

  3. henry's law states that .. c(O2) = kH * P(O2) where .. c(O2) = concentration of...1).. c(O2) = 0.00130 M/atm * 0.210 * 1.00atm = ___ M .. (2).. c(O2) = 0.00130 M/atm * 0.210 * 0.894atm = ___ M .. (3).. 4.80L...

    2 Answers · Science & Mathematics · 11/05/2020

  4. P1 / T1 = P2 / T2.  Substitute and solve for P2.  Remember to convert deg C to K for gas problems.  About 0.47 atm.

    2 Answers · Science & Mathematics · 30/04/2020

  5. (767 L) x (–29.1 + 273) K / (17.9 + 273) K x (752 mmHg / 337 mmHg) = 1435 L

    1 Answers · Science & Mathematics · 24/04/2020

  6. ...1.10 atm) x (0.0100 L) / ((0.082057366 L atm/K mol) x (288.5 K)) = 4.647 × 10^-4 mol (0.04411 g) / (4.647 × 10^-4 mol) = 94.921 g/mol (25.305% of 94.921 g/mol) / (12.01078 g C/mol) = 1.9999 (74.695% of 94.921 g/mol) / (35.4532 g Cl/mol) = 1.9999 ...

    2 Answers · Science & Mathematics · 23/04/2020

  7. ... = (1.124 atm - 0.373 atm) x (2.00 L) / ((0.082057366 L atm/K mol) x (30 + 273) K) = 0.0604101 mol CO2 reacted 2. Let...

    1 Answers · Science & Mathematics · 22/04/2020

  8. ...n RT (705/760) (0.195 L) = n (0.08206 Latm/molK)(298 K) n = 7.40X10^-3 mol Cl2 7.40X10^-3 mol Cl2 ...

    1 Answers · Science & Mathematics · 22/04/2020

  9. (349 cm^3) x (2.02 atm / 0.958 atm) x (23 + 273) K / (31.1 + 273) K = 716 cm^3

    3 Answers · Science & Mathematics · 18/04/2020

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