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  1. n / V = P / RT = (889.2 Torr) / ((62.36367 L Torr/K mol) x (173 + 273) K) = 0.031969 mol/L (28.01344 g N2/mol) x (0.031969 mol/L) = 0.89556 g/L = 0.896 g/L

    3 Answers · Science & Mathematics · 24/05/2019

  2. ... is such a table Metal Ion Caesium Cs Francium Fr Rubidium Rb Potassium K Sodium Na Lithium Li Barium Ba...

    2 Answers · Science & Mathematics · 31/08/2019

  3. ... temperature and has a value of 0.9340 g/cm³ at −180 °C (93 K). Given that density of water varies between 0.9998 and 0.9997 (close to...

    2 Answers · Science & Mathematics · 29/01/2020

  4. ... = 0.535 R = 22.4 ÷ 273 Let’s convert the temperature from˚C to ˚K. T = 24.6 + 273 = 297.6˚K Now we can determine the ...

    2 Answers · Science & Mathematics · 24/05/2019

  5. ... = (100 kPa) x (6.409 L) / ((8.3144626 L kPa/K mol) x (25.0 + 273.15) K) = 0.258536 mol H2 (0.258536 mol H2...

    1 Answers · Science & Mathematics · 18/06/2019

  6. ...by each 2 moles of NH4NO3 that decompose. (1.00 bar) x (205 + 273) K / (25 + 273) K = 1.604 bars air (5.00 g NH4NO3) / (80.0434 g...

    3 Answers · Science & Mathematics · 24/05/2019

  7. ...(g) + K2O3Si(s) + 5 Na2O3Si(s) c) (100 g NaN3) / (65.00987 g NaN3/mol) = 1.53823...1.53823 mol NaN3) x (8.3144626 L kPa/K mol) x (25.0 + 273.15) K / (101 kPa) = 37.8...

    2 Answers · Science & Mathematics · 19/06/2019

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