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  1. ...(+) + e ---> Na E = -2.71V K(+) + e ---> K E = -2.93V Rb(+) + e ---> Rb E = -2.93V Cs(+) + e ---> Cs E = -2.92V From the above values...

    4 Answers · Science & Mathematics · 27/04/2007

  2. A) The oxidation number of I goes from -2 to 0. That is, it increases. That is one definition of oxidation.

    1 Answers · Science & Mathematics · 27/02/2014

  3. A. Na has the electron configuration 1s2 2s2 2p6 3s1.

    1 Answers · Science & Mathematics · 07/11/2011

  4. Volume is proportional to temperature. If the volumes doubles, then the temperature (in K) must also double. (30 + 273) x 2 = 606 K = 333°C

    1 Answers · Science & Mathematics · 06/05/2015

  5. K = (c(PCl3)* c(Cl2)) / c(PCl5) Put in the values...042 c(PCl5) = c0 -x c(PCl3) = c0 + x c(Cl2) = c0 +x K = [ (c(PCl3)+x)* (c(Cl2))+x) / (c(PCl5)-x) ] Now solve for...

    1 Answers · Science & Mathematics · 23/10/2013

  6. noble gases are very stable because they almost have octet. Thats why noble gases don't react much.

    4 Answers · Science & Mathematics · 05/10/2012

  7. K = {[C]^2*[D]} / {[A][B... in equilibrium . Since K needs to be larger 1... of the products 'C' & 'D' need to be...

    2 Answers · Science & Mathematics · 02/01/2011

  8. K = (c(PCl3)* c(Cl2)) / c(PCl5) Put in the values...042 c(PCl5) = c0 -x c(PCl3) = c0 + x c(Cl2) = c0 +x K = [ (c(PCl3)+x)* (c(Cl2))+x) / (c(PCl5)-x) ] Now solve for...

    1 Answers · Science & Mathematics · 23/10/2013

  9. K=[C]^2 x [D] / [A]3 x [B]^2 =6^2 x 4 /1.5^3 x 0.85^^2 =59.25

    1 Answers · Science & Mathematics · 13/11/2013

  10. K = (c(PCl3)* c(Cl2)) / c(PCl5) Put in the values...042 c(PCl5) = c0 -x c(PCl3) = c0 + x c(Cl2) = c0 +x K = [ (c(PCl3)+x)* (c(Cl2))+x) / (c(PCl5)-x) ] Now solve for...

    1 Answers · Science & Mathematics · 23/10/2013

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