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  1. V = nRT / P = (12.3 g Cl2 / (70.9064 g Cl2/mol)) x (8.3144626 L kPa/K mol) x (13 + 273) K / (96.4 kPa) = 4.28 L

    1 Answers · Science & Mathematics · 28/05/2020

  2. (36.0 L) x (101.325 kPa / 112 kPa) x (273 K) / (27 + 273) K = 29.6 L

    1 Answers · Science & Mathematics · 28/05/2020

  3. 101.1 kPa - 2.200 kPa = 98.9 kPa So answer a) Absolute zero: b) A substance has no molecular motion density: b) Decreases b) i) and iii) (0.707 g/L) x (22.4 L/mol) = 15.8 g/mol The gas with a molar mass like that is CH4...

    1 Answers · Science & Mathematics · 15/05/2020

  4. ΔrG° = - RT ln Keq ΔrG° = - 8.314 J/molK (273.15 + 31.1 K) ln (2.3X10^3) = 1.96X10^4 J/mol = 19.6 kJ/mol

    1 Answers · Science & Mathematics · 11/04/2020

  5. ...-m^2/C^2 so E = 9x10^9*3*10^-9/(0,05)^2 = 1200 N/C Part K  q2 has a radial position of r1 = sqrt(2^2 +(-4)^2) = sqrt(16+4) = sqrt(20...

    2 Answers · Science & Mathematics · 10/02/2020

  6. ...fit the defining Pascal's Triangle property: C(m,k) + C(m,k-1) = C(m+1,k) [0 < k <= m].  ...

    1 Answers · Science & Mathematics · 09/02/2020

  7. ...integer. Therefore, if we choose k (k > ceiling(k/2)) integers from T then at least two ...y∈S such that a≠b, {a,b}≠{x,y} and b−a=y−x. c. Let S = {s1,s2, ... ,sk} and s1<...

    1 Answers · Science & Mathematics · 09/02/2020

  8. find the mass of the sprite m_s = 1.037g/mL * 355mL = 368 g so 368g * 4.10J/g·ºC * (25.0ºC - T) = 6*90.7g * 1.670J/g·ºC * (T - -10.0ºC) T = 11.8º Maybe you missed the sign on the -10.0ºC; or...

    1 Answers · Science & Mathematics · 09/02/2020

  9. ... (x+n+1)Cn .    We know mCk = (m-1)Ck + (m-1)C(k-1) because  mCk  = m! / [(m-k)!k!]  = (m-1)!*m / [(m-k)!k!]  = (m-1)!*((m-k...

    2 Answers · Science & Mathematics · 08/02/2020

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