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Mark. Marc feels a bit pretentious to me for some reason? Like I imagine a flashy guy who talks a lot about his expensive car. 

The integrated rate law for a 2nd order reaction is: 1/[B] = kt + 1/[B]o 1/[B] = 2.45X10^-2 M-1min-1 (1.8 min) + 1/(6.9 M) [B] = 5.3 M

Won't use there notation  n_ C _ k    , I will write as    C (n, k )       so both...7!) = 10*9*8/ 3*2*1  =   10*9*4/3  = 10*3*4  = 120  C (10,3) (1/4)^3 (3/4)^7 =  120* ( 3^7/ 4^10)  =  = 262440...

N = kx + c plug in the numbers to determine constants 200 = k (7) + c 150 = k (9) + c c = 200 – 7k c = 150 – 9k 200 – 7k = 150 – 9k 9k – 7k = 150 – 200...

K = √s(s-a)(s-b)(s- c ) where s = (1/2) (a + b + c ) s= (1/2)(100 + 50 +75) = 112.5 K = √s(s-a)(s-b)(s- c )  K = √112.5(112.5 -100)(112.5 -50)(112.5 - 75) = 1815.46 1815.46 x $ 3.00 = $. 5446.38

...) / ((0.08206 L⋅atm/(mol⋅ K )) × (29 + 273) K ) = 0.0119219 mol = 0.01192 mol H2 So you are correct about Parts a), B), and C ). Part D) Given: x + y = 0.250...

... equal, it looks like "x" is the only unknown, because K = 9.0x10^9 Nm^2/ C ^2 and Q = 1.5 microcoulombs, and k = 10 N/m.  So...

Specific heat capacity of water is 4179.6 [Joules / (kg * K )] The enthalpy of fusion is 333.55 [kJ / kg] Specific...