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The expression

**k**& 1 is evaluated first. & is a bitwise AND operator...2 Answers · Computers & Internet · 06/12/2014

...be combined to get the simplest expression. If you code it in

**C**++, you need to emulate the steps in the algorithm, which is more difficult...1 Answers · Computers & Internet · 22/03/2008

...global variable (it is defined outside any function),

**C**allocates static storage for it and initialises...zero. Your code says if (a[i][j] > 0) { b[**k**] = a[i][j];**k**++; } The**k**++ increments the pointer...1 Answers · Computers & Internet · 18/11/2012

P =

**C**xor**K**is a triangular equation. P,**C**, and**K**form the points...xor operation of the two known variables: P =**C**xor**K C**= P xor**K K**=**C**xor P Draw out the truth...1 Answers · Computers & Internet · 18/12/2012

...four equations above and get the other input value. No matter what value

**k**has, it will have a value of all zeros after**k**=**k**^**k**(which is...2 Answers · Computers & Internet · 27/03/2012

Yes it is possible to do it in

**c**http:// cs .smu.ca/~r_zhang/code/kmeans.**c**There are...1 Answers · Computers & Internet · 20/09/2013

.... Or you could swap the

**k**row with the**k**+1 row, and the**k**+1 row with the**k**+2 row, etc until the end of the array. Or, much better, you could switch to**C**++ and let the language do the work for you with a single call to the built-in...1 Answers · Computers & Internet · 05/12/2010

...if(

**c**< -273.15) throw Below_abs_zero(); else double**k**=**c**+ 273.15; return**k**; } actually looks like this, if you add the braces explicitly...5 Answers · Computers & Internet · 18/09/2011

void main() { //variables int

**k**,n; //input cout << "**k**: "; cin >>**k**...2 Answers · Computers & Internet · 08/12/2009

In this line: int a[3][3],b[3][3],

**c**[3][3],i,j,**k**,**c**; you have the variable**c**defined twice, once as an...3;j++) {**c**[i][j] = 0; for(int**k**=0;**k**<3;**k**++) {**c**[i][j] =**c**[i][j] + a[i][**k**]*b[**k**][j]; } besides, it doesnt...3 Answers · Computers & Internet · 16/12/2008

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