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  1. False; you subtract 273 from both sides. K = C + 273 K - 273 = C + 273 - 273 K - 273 = C

    8 Answers · Science & Mathematics · 28/01/2010

  2. Using the binomial expansion of (3+1)^n = ∑( k=0 until n) 3^k C(n,k).

    1 Answers · Science & Mathematics · 18/06/2011

  3. c = k ⊕ m c ⊕ m = k ⊕ m ⊕ m = k So k = c ⊕ m = 1001010001010111 ⊕ 0010010000101100 = 1011000001111011

    1 Answers · Science & Mathematics · 12/03/2013

  4. ... in the formula: since k = n - (n-k), we have: C(n, k) = n! / (k! (n-k)! ) C(n, n-k) = n! / ((n-k)! (n - (n-k))! = n! / ( (n-k)! k! )

    1 Answers · Science & Mathematics · 14/03/2012

  5. log k= log(v^c) +log p=log(p*v^c) so k=(v^c)*p. just remember : log(a^b)=b log(a) and log a+ log b= log(a*b)

    1 Answers · Science & Mathematics · 27/04/2012

  6. If x = -b, you have a 0 in the denominator. Division by 0 is undefined. Can you explain why?

    1 Answers · Science & Mathematics · 20/08/2008

  7. k - 10d = c/4 4k - 40d = c or c = 4k - 40d

    5 Answers · Science & Mathematics · 23/04/2011

  8. Assuming that k and c are just constants, the equation is separable, divide both sides by (c - y) and multiply the differential across: 1/(c - y) * dy = k * dx Integrate both sides: -ln(c - y) = kx + C Make y the subject, divide both...

    3 Answers · Science & Mathematics · 17/08/2013

  9. log k= log(v^c) +log p=log(p*v^c) so k=(v^c)*p. just remember : log(a^b)=b log(a) and log a+ log b= log(a*b)

    2 Answers · Science & Mathematics · 24/04/2010

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