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  1. ... , assume that (#1) stands when m = k . That is , "(2^k)C(1), (2^k)C(2), ... , (2^k)C(2^k-1) are all even" ---(#2...

    2 Answers · Science & Mathematics · 03/10/2019

  2. ...fit the defining Pascal's Triangle property: C(m,k) + C(m,k-1) = C(m+1,k) [0 < k <= m].  ...

    1 Answers · Science & Mathematics · 09/02/2020

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