...x E 0.200 - x 0.200 - x 2x k = [ C ]/([A][B]) = 64.5 k = (2x)^2/[( 0.200 - x)( 0.200 - x)] = 64...

3 Answers · Science & Mathematics · 28/03/2021

a)

**K**= [PCl3][Cl2]/[PCl5] = 85 Let x = [PCl3...1 Answers · Science & Mathematics · 10/04/2021

..., where A is the amount of iridium-192. ==== b. Rate constant, k = ln(2)/t½ = ln(2)/(74 days) = 0.009367 day⁻¹ ≈ 0.00937 day⁻¹ ==== c . No. of half-lives = (5 × 365.25 days) / (74 days) = 24...

1 Answers · Science & Mathematics · 24/03/2021

...atm) x (12.0 L) / ((4.00 mol x (0.082057366 L atm/ K mol)) = 204.7 K = - 68.4 ° C 3. P = nRT / V = (3 mol) x (0.082057366 L atm/ K ...

1 Answers · Science & Mathematics · 16/04/2021

(3.40 L) / (20.0 + 273.15)

**K**x (20.0 + 10.0 + 273.15)**K**x (1.50 atm / 2.50 atm) = 2.11 L4 Answers · Science & Mathematics · 26/03/2021

...have: V = 10.0 L n = 55 mol T = 25.0 oC = (25.0+273)

**K**= 298K we have below equation to be used: P * V = n...1 Answers · Science & Mathematics · 25/03/2021

n/V = P / RT = 1.05 atm / ((0.082057366 L atm/

**K**mol) x (25.1 + 273.15)**K**) = 0.042903 mol/L (0.042903 mol/L) x (30.07 g/mol) = 1.29 g/L1 Answers · Science & Mathematics · 15/04/2021

... know all so to solve for V, you must put temperature in degrees K (283.45K) and use an R in units of L-atm/deg-mol...

3 Answers · Science & Mathematics · 18/04/2021

P = nRT / V = (0.200 mol) x (0.082057366 L atm/

**K**mol) x (41 + 273)**K**/ (9.00 L) = 0.5726 atm of third gas 0.355 atm + 0.817 atm + 0.5726 atm = 1.74 atm total1 Answers · Science & Mathematics · 15/04/2021

... = (716.4 mmHg) x (2.72 L) / ((62.36367 L mmHg/ K mol) x (10.2 + 273.15) K ) = 0.110273 mol (0.354 g) / ((22.414 L/mol...

1 Answers · Science & Mathematics · 18/04/2021