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  1. ... and z-components like this: a - b = (3 - (-1))i + (1 -2)j + (-1 - 5)) k = 4i - 1j – 6k Then c •(a - b)  = (0i + 2j- 3k)•(4i - 1j – 6k) = 0*4 + 2*(-1) + (-3)(-6) = 16 ...

    2 Answers · Science & Mathematics · 15/11/2020

  2. a) Na, Li, K , Cs Li -- Na  -- K -- Cs b) O+ , O-, O...

    1 Answers · Science & Mathematics · 19/11/2020

  3. ...5.0 + 273.15) K × (3.34×10^3 L) / (1.67×10^3 L) = 556.3 K = 283° C 2. Since the pressure increased, the volume must have decreased...

    2 Answers · Science & Mathematics · 04/11/2020

  4. At constant volume  P₁/T₁ = P₂/T₂ T₂ = P₂T₁/P₁ T₂ = (2.31 atm)(0 + 273.15 K )/(2.19 atm) T₂ = 288 K T₂ = (288 - 273.15) ° C = 14.9° C

    1 Answers · Science & Mathematics · 21/11/2020

  5. we know PV = nRT P = CRT P - pressure C - Concentration = number of moles / volume = n / v R = gas constant = 0.0821 lit.atm/ K .mol T = temperature = 200c + 273 K =293K P = 4.8 * 10-2...

    2 Answers · Science & Mathematics · 21/11/2020

  6. ...need to do the calculation in K (by the way, not shown as ° K , only K is used) (100.0 g) (x - 26.3) (4.184) = (75.0 g) (75 - x) (4.184) 100x - 2630 = 5625 - 75x 175x = 8255 x = 47.2 C https://www.chemteam.info/Thermochem/MixingWater.html

    3 Answers · Science & Mathematics · 10/11/2020

  7. ... * volume / (gas constant * Temperature) temperature is 28 C , change this to kelvin Temperature kelvin = 28 + 273.15 = 301.15 K Pressure is 3.5×10?6 torr , change this to atm: 3.5×10?6 torr...

    1 Answers · Science & Mathematics · 27/10/2020

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