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(a) By F-32 = 9C/5 =>57-32 = 9C/5 =>

**C**= (25 x 5)/9 =>**C**= 13.89* (b) by T = 273+***C**=>T = 273+13.89 =>T = 286.89***K**2 Answers · Science & Mathematics · 12/01/2012

That is more likely because the units are not related to each other.. kN/

**C**is the rate while**k**is the quantity of something. Good luck!1 Answers · Science & Mathematics · 29/09/2012

L-Band 40 - 60 GHz S-Band 2 - 4 GHz X-Band 7 -12.5 GHz

**C**-Band 4 - 8 GHz**K**-Band 20 - 40 GHz1 Answers · Science & Mathematics · 24/11/2007

**C**is incorrect 289 + 273 = 562**K**1 Answers · Science & Mathematics · 28/04/2013

Substract 56C from 30C to get the difference in deg

**C**Convert each temperature to deg F, subtract as above to get the difference in deg F Convert each temperature to deg**K**, subtract as above to get the difference in deg**K**Convert each temperature...1 Answers · Science & Mathematics · 17/09/2014

...at the freezing point of water, which is (at 1 atm): 32 F, 0

**C**, or 273**K**. Those all correspond to the same temperature, just in different units...2 Answers · Science & Mathematics · 08/12/2008

d is your answer ,it also works for capacitance . the resistance in the circuit equals the total of the resistor values .

4 Answers · Science & Mathematics · 28/12/2009

... = 17 deg.

**C**= 290.15**K**T_sea = 3 deg.**C**= 276.15**K**= Tsurr**C**_sea =3.985 J/g.**K**Assume mass of the sea is so high...1 Answers · Science & Mathematics · 26/09/2010

...:m/sec : velocity, speed B:m: distance, displacement, length

**C**:ft/sec: velocity, speed D:hours: time E:m/sec...velocity, speed I:kg: mass J:ft: distance, displacement, length**K**:km/hr^2: acceleration1 Answers · Science & Mathematics · 25/09/2008

...the same as 3.6E-4 v/m what you have done is use F =

**K**q1 q2 / r^2 where q2 is 1**C**' then F/q2 = (N/**C**) = E When you get a good...1 Answers · Science & Mathematics · 25/02/2016

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