Yahoo Web Search

  1. Ad
    related to: K.C
  1. (a) By F-32 = 9C/5 =>57-32 = 9C/5 => C = (25 x 5)/9 => C = 13.89* (b) by T = 273+* C =>T = 273+13.89 =>T = 286.89* K

    2 Answers · Science & Mathematics · 12/01/2012

  2. That is more likely because the units are not related to each other.. kN/ C is the rate while k is the quantity of something. Good luck!

    1 Answers · Science & Mathematics · 29/09/2012

  3. L-Band 40 - 60 GHz S-Band 2 - 4 GHz X-Band 7 -12.5 GHz C -Band 4 - 8 GHz K -Band 20 - 40 GHz

    1 Answers · Science & Mathematics · 24/11/2007

  4. C is incorrect 289 + 273 = 562 K

    1 Answers · Science & Mathematics · 28/04/2013

  5. Substract 56C from 30C to get the difference in deg C Convert each temperature to deg F, subtract as above to get the difference in deg F Convert each temperature to deg K , subtract as above to get the difference in deg K Convert each temperature...

    1 Answers · Science & Mathematics · 17/09/2014

  6. ...at the freezing point of water, which is (at 1 atm): 32 F, 0 C , or 273 K . Those all correspond to the same temperature, just in different units...

    2 Answers · Science & Mathematics · 08/12/2008

  7. d is your answer ,it also works for capacitance . the resistance in the circuit equals the total of the resistor values .

    4 Answers · Science & Mathematics · 28/12/2009

  8. ... = 17 deg. C = 290.15 K T_sea = 3 deg. C = 276.15 K = Tsurr C _sea =3.985 J/g. K Assume mass of the sea is so high...

    1 Answers · Science & Mathematics · 26/09/2010

  9. ...:m/sec : velocity, speed B:m: distance, displacement, length C :ft/sec: velocity, speed D:hours: time E:m/sec...velocity, speed I:kg: mass J:ft: distance, displacement, length K :km/hr^2: acceleration

    1 Answers · Science & Mathematics · 25/09/2008

  10. ...the same as 3.6E-4 v/m what you have done is use F = K q1 q2 / r^2 where q2 is 1 C ' then F/q2 = (N/ C ) = E When you get a good...

    1 Answers · Science & Mathematics · 25/02/2016

  1. Ads
    related to: K.C
  1. Try asking your question on Yahoo Answers