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  1. ...at t = 0) (180) t is the time since measurement started (varies) k is the cooling constant (unknown) Let's first put in...

    1 Answers · Science & Mathematics · 20/07/2020

  2. let q2 = 1 C F = k q1 q2 / d^2 F = 8.99E9 (-5.77E-9)(1) / 0.450^2 = -256 ...

    2 Answers · Science & Mathematics · 13/01/2020

  3. a/ y = a(2^(-t/30))=a(0.97716)^t, 1-r = 0.97716 ---> r = 0.02284 = 2.284%  b/ y = a(e^(kt)) = a(0.97716)^t solve for k c / and d/ you can do

    1 Answers · Science & Mathematics · 01/06/2020

  4. k = (22.80-12.49)/100 = 0.1031 cm / ° C (18.87-12.49) / k = 61.88 ° C   (14.72-12.49) / k = 21.63 ° C  

    1 Answers · Science & Mathematics · 22/06/2020

  5. ... 1/T₂ = 3.2301 × 10⁻³ New temperature, T₂ = 310 K = 37° C ==== B. When T₁ = 273 + 25 = 298 K , k₁ = 0.0120...

    2 Answers · Science & Mathematics · 13/02/2020

  6. ... temperature, T₂ = (298.2 K ) × (3P/P) = 894.6 K = 621.4 ° C ==== If the gas is heated so that both the pressure and volume...

    3 Answers · Science & Mathematics · 07/07/2020

  7. False I've known for many years there's a K . C . in both states, what makes it embarrassing  (though seriously...

    7 Answers · Entertainment & Music · 09/02/2020

  8. ...23.67 x 2.44 x (T2-288) Solving for T2 T2 = 302.11 K = 29.11 C [final temperature] Please Rate!! Comment 

    1 Answers · Science & Mathematics · 15/09/2020

  9. ...θ + 53.1) Therefore, -5k ≤ k (3sinθ + 4cosθ) ≤ 5 k   Then, -5k + c ≤ k (3sinθ + 4cosθ) + c ≤ 5k + c Hence, -5k + c = -37 and 5k + c = 43 ...

    1 Answers · Science & Mathematics · 10/06/2020

  10. F u c k y o u. You lying mutha f u c k a. 

    3 Answers · Entertainment & Music · 31/08/2020

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