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...a dog produced by kc champions.... also..... (So much for

**k**.**c**'s and their blather me thinks) Show collies...9 Answers · Pets · 09/04/2018

...those probabilities. We use the binomial probability: P(X=

**k**) =**C**(n,k) * p^k * q^(n-k) n : number of total fuses tested (3...1 Answers · Science & Mathematics · 11/03/2018

...ln|2x - 1|] + K; (1/16)*ln|2x - 1| + ((x^3)/6) + ((x^2)/8) + (x/8) - 11/96 +

**K**;**C**= K - (11/96); ((x^3)/6) + ((x^2)/8) + (x/8) + (1/16)*ln|2x - 1| + C1 Answers · Science & Mathematics · 23/02/2018

*** (9) *** from the arrhenius equation ..

**k**= Ao exp(-Ea / RT) assuming Ao, Ea, R are all +, then increasing T increases**k**.... . .plug in values and try it if you need to. *** 10 *** we can assume activation energy...2 Answers · Science & Mathematics · 06/03/2018

His longevity with the Boston Celtics.

2 Answers · Sports · 11/02/2018

... wavelength is ratio of speed of sound and frequency, λ = c/f 0.0415 m =

**k*****c**/f f =**k*****c**/ 0.0415 m We see smallest frequency occurs when k...1 Answers · Science & Mathematics · 30/01/2018

Seems basically correct, assuming the first "x" in your a x (x^

**k**) is supposed to be a multiplication symbol, not a variable. You could divide through by 3 to have .. log(y) = (**k**/3)*log(x) +log(a)/3 .. Y = log(y) .. m =**k**/3 .. X = log(x) ..**c**= log(a)/3...1 Answers · Science & Mathematics · 30/01/2018

... immediately. Then Q increases and finally Q =

**K**.**C**. The equilibrium position shifts to left and less CH₂ is...1 Answers · Science & Mathematics · 23/01/2018

...248 L) / ((3.33 x 10^-3 mol) x (62.36367 L torr/K mol)) = 872

**K**(**c**) P = nRT / V = (0.0485 mol) x (0.08205746 L atm/K...2 Answers · Science & Mathematics · 18/01/2018

Rate =

**k**[A]^m[B]^p Divide trial 2 by trial 1:**k**(1.50)^m(1.50)^p = 1.3 x 10^-2 -----------------------------------------**k**(0.50)^m(1.50)^p = 4.2 x 10^-3 (3)^m = 3 m = 1 ; reaction is first order in A Divide trial 3 by trial 2: (3.00)^1(3.00)^p = 5.2 x 10^-2...1 Answers · Science & Mathematics · 11/01/2018