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...distribution, the probability of exactly k successes is given by f(

**k**) =**C**(n,k) p^k (1 - p)^(n - k), for k in {0, 1, 2, . . . , n} (otherwise f(k) = 0), where...1 Answers · Education & Reference · 01/04/2007

... = a(x - h)² + k where h = -b/(2a) - - - > EQUATION 1

**k**=**c**- b²/(4a) - - - > EQUATION 2 So the first problem...1 Answers · Education & Reference · 09/02/2011

...distribution, the probability of exactly k successes is given by f(

**k**) =**C**(n, k) p^k (1 - p)^(n - k), for k in {0, 1, 2, . . . , n} (otherwise f(k) = 0), where...2 Answers · Education & Reference · 17/06/2012

...that the probability of exactly k successes is given by f(

**k**) =**C**(n,k) p^k (1 - p)^(n - k), for k in {0, 1, 2, . . . , n} (otherwise f(k) = 0), where...2 Answers · Education & Reference · 28/02/2010

...distribution, the probability of exactly k successes is given by f(

**k**) =**C**(n,k) p^k (1 - p)^(n - k), for k in {0, 1, 2, . . . , n} (otherwise f(k) = 0), where...3 Answers · Education & Reference · 17/04/2007

...distribution, the probability of exactly k successes is given by f(

**k**) =**C**(n,k) p^k (1 - p)^(n - k), for k in {0, 1, 2, . . . , n} (otherwise f(k) = 0), where...3 Answers · Education & Reference · 24/04/2007

...the probability of k successes out of N trials as P(

**k**) =**C**(N,k) x p^k x (1 - p)^(N - k), where C(N,k) is...5 Answers · Education & Reference · 18/03/2007

... I elements are soluble (Li+, Na+,

**K**+,**Cs**+, Rb+). Exceptions to this rule are rare. Salts ...5 Answers · Education & Reference · 22/08/2010

k=qc/c+qt, solve for c

**k**(**c**+ qt) = qc {multiplied both sides by (c + qt)} kc + kqt = qc {...2 Answers · Education & Reference · 07/11/2011

**k**) =**C**(n,k) p^k (1 - p)^(n - k), for k in {0, 1, 2, . . . , n} (otherwise f(k) = 0), where...2 Answers · Education & Reference · 08/12/2009

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