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  1. ...distribution, the probability of exactly k successes is given by f(k) = C(n,k) p^k (1 - p)^(n - k), for k in {0, 1, 2, . . . , n} (otherwise f(k) = 0), where...

    1 Answers · Education & Reference · 01/04/2007

  2. ... = a(x - h)² + k where h = -b/(2a) - - - > EQUATION 1 k = c - b²/(4a) - - - > EQUATION 2 So the first problem...

    1 Answers · Education & Reference · 09/02/2011

  3. ...distribution, the probability of exactly k successes is given by f(k) = C(n, k) p^k (1 - p)^(n - k), for k in {0, 1, 2, . . . , n} (otherwise f(k) = 0), where...

    2 Answers · Education & Reference · 17/06/2012

  4. ...that the probability of exactly k successes is given by f(k) = C(n,k) p^k (1 - p)^(n - k), for k in {0, 1, 2, . . . , n} (otherwise f(k) = 0), where...

    2 Answers · Education & Reference · 28/02/2010

  5. ...distribution, the probability of exactly k successes is given by f(k) = C(n,k) p^k (1 - p)^(n - k), for k in {0, 1, 2, . . . , n} (otherwise f(k) = 0), where...

    3 Answers · Education & Reference · 17/04/2007

  6. ...distribution, the probability of exactly k successes is given by f(k) = C(n,k) p^k (1 - p)^(n - k), for k in {0, 1, 2, . . . , n} (otherwise f(k) = 0), where...

    3 Answers · Education & Reference · 24/04/2007

  7. ...the probability of k successes out of N trials as P(k) = C(N,k) x p^k x (1 - p)^(N - k), where C(N,k) is...

    5 Answers · Education & Reference · 18/03/2007

  8. ... I elements are soluble (Li+, Na+, K+, Cs+, Rb+). Exceptions to this rule are rare. Salts ...

    5 Answers · Education & Reference · 22/08/2010

  9. k=qc/c+qt, solve for c k(c + qt) = qc {multiplied both sides by (c + qt)} kc + kqt = qc {...

    2 Answers · Education & Reference · 07/11/2011

  10. ...distribution, the probability of exactly k successes is given by f(k) = C(n,k) p^k (1 - p)^(n - k), for k in {0, 1, 2, . . . , n} (otherwise f(k) = 0), where...

    2 Answers · Education & Reference · 08/12/2009

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