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  1. (1550 L) x (67 + 273) K / (38 + 273) K = 1695 L

    1 Answers · Science & Mathematics · 03/07/2019

  2. ... must be in an absolute temperature scale. Kelvin will do nicely. K = C + 273.15 P1V1 / T1 = P2V2 / T2 ............ combined...

    2 Answers · Science & Mathematics · 26/06/2019

  3. P = nRT / V = (0.683 mol) x (62.36367 L mmHg/K mol) x (10.0 + 273.15) K / (26.1 L) = 462 mmHg...

    1 Answers · Science & Mathematics · 25/06/2019

  4. n = PV / RT = (0.683 atm) x (26.1 L) / ((0.082057338 L atm/K mol) x (10.0 + 273.15) K) = 0.767 mol --------------------- (1.41 atm) x (0.851 L) / ((0.082057338 L atm/K mol) x (275 K)) = 0.0532 mol

    1 Answers · Science & Mathematics · 25/06/2019

  5. (9.70 L) x (93 + 273) K / (63 + 273) K = 10.6 L (288 + 273) K x (682 mL / 400 mL) = 956.51 K = 683°C

    1 Answers · Science & Mathematics · 25/06/2019

  6. P = nRT / V = (1.60 g Xe / (131.293 g Xe/mol)) x (0.082057338 L atm/K mol) x (22.0 + 273.15) K / (0.590 L) = 0.500 atm

    1 Answers · Science & Mathematics · 25/06/2019

  7. ...5555555.... / 2 = C 51 + 0.2777777777.... = C 51.2777777.... = C 51.28 = C K = C + 273.15 K = 51.27777.... + 273.15 K = 324.4277777.... K...

    3 Answers · Science & Mathematics · 24/06/2019

  8. (787.1°F - 32) x (5/9) = 419.5°C 419.5°C + 273.15 = 692.65 K

    1 Answers · Science & Mathematics · 18/07/2019

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