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  1. (21.56 + 273.15) K x (767 mmHg / 725 mmHg) = 311.7829 K (311.7828 K - 273.15 K) = 38.63°C

    4 Answers · Science & Mathematics · 06/08/2019

  2. ... E° = (8.314 J/molK x 298K / 4 / 96,458 C/mol) ln 9.82x10^-8 E° = -1.04V The negative cell potential ...

    1 Answers · Science & Mathematics · 07/08/2019

  3. ...the pressure and volume are inversely proportional: PV = k. The product of the pressure and volume should be the same... = -0.803 / 0.003 ....... when P = 0 T = -268 C Percent error = |(-273 - (-268)) / -273| x 100 = 1.83% .

    2 Answers · Science & Mathematics · 03/08/2019

  4. ... constant and cancel it .. (4) plug and chug.... remember T must be absolute.. K or R.. never °C nor °F you do that and you don't need to remember boyles law, charles...

    3 Answers · Science & Mathematics · 31/07/2019

  5. (38.6 + 273.15) K x (0.798 L / 4.64 L) x ((125 kPa x 7.50062 torr/kPa) / 685 torr) = 73.385 K = -200.°C

    2 Answers · Science & Mathematics · 26/07/2019

  6. ... {2+}, Br {-}, Li {+}, NO3 Hg2Br2 will ppt c. Ag {+}, Br {-}, Ca {+2}, SO4 {2-} both AgBr and Ag2SO4 will ppt. d. K{+} NO3 {-}, Na {+}, Br {-} none of the possible procucts will...

    1 Answers · Science & Mathematics · 27/07/2019

  7. ... * (T2 / T1) plug and chug .. P2 = 2.25atm * ( (75+273.15 K) / (30+273.15 K) ) = 2.58 atm

    2 Answers · Science & Mathematics · 24/07/2019

  8. ... = 51,416.8473 ÷ 72.128 The temperature is approximately 713˚K. ˚C = (51,416.8473 ÷ 72.128) – 273 The temperature is approximately 440˚...

    3 Answers · Science & Mathematics · 23/07/2019

  9. P = nRT / V = (95.5 mol) x (0.082057338 L atm/K mol) x (89.00 + 273.15) K / (59.5 L) = 47.7 atm

    1 Answers · Science & Mathematics · 23/07/2019

  10. ...4) plug in the data, chug out the results.. remember T must be absolute.. K or R... never °C nor °F ********** this problem start with .. P1V1 (n1T1) = P2V2...

    2 Answers · Science & Mathematics · 23/07/2019

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