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Ok. 273

**K**= 0**C**so therefore 330C = 330 + 273 = 603K**C**.5 Answers · Science & Mathematics · 21/06/2010

By the Binomial Theorem, (1 + x)^n = sum(

**k**=0 to n)**C**(n,**k**) x^**k**. Differentiating both sides twice, we get n(n - 1) (1 + x...1 Answers · Science & Mathematics · 19/10/2009

...28 +

**c****c**= 6k - 10 12k = 28 + 6k - 10 6k = 18**k**= 3**c**= 6(3) - 10**c**= 8**k**+**c**= 3 + 8 = 111 Answers · Science & Mathematics · 11/01/2009

n *

**C**(n-1,**k**-1) = n * [(n-1)! / ((**k**-1)! (n-**k**)!)] = n! / ((**k**-1)! (n-**k**)!) =**k*** [n! / (**k**! (n-**k**)!)] =**k*****C**(n,**k**). I hope this helps!1 Answers · Science & Mathematics · 20/11/2011

ƒ(

**k**) = √[**k**+ (**k**−**c**)^2], assuming**c**is a constant, and**k**is the only variable. ƒ...v, by chain rule, we get: ƒ'(**k**) = u' ⋅ v ⋅ u^(v - 1) ƒ'(**k**) = [1 + 2(**k**−**c**)] ⋅ 1/2 ⋅ [**k**+ (**k**−**c**)^2]^(-1/2) ƒ'(**k**) = (1 + 2k − 2c) / (2√[**k**+ (**k**−**c**...3 Answers · Science & Mathematics · 23/02/2013

A = 4k = 0i + 0j + 4k B = 8i +

**k**= 8i + 0j +**k****C**= 3i - 4j = 3i - 4j + 0k Now, (A • B) = (0*8 + 0*0 + 4*1) = 4...2 Answers · Science & Mathematics · 24/09/2012

...respectively. Reference (2) gives formulas for h=-b/2a and

**k**=**c**- [(b^2)[(4a)]. Using these we answer the questions that h = -(-12)/[2...1 Answers · Science & Mathematics · 21/02/2013

..., but that'd just be ridiculous). However, the answer is: °

**C**= °**K**- 273.16 °**C**= 300 - 273,16 = 26.84°**C**, or, rounded off, to 27...3 Answers · Science & Mathematics · 08/02/2008

it's not

**K**instead of**C**, it's just**K**. names are ...original greek name Νικολαος - there's no**C**either, but every nation adapt names to their ...2 Answers · Society & Culture · 06/08/2012

...http://en.wikipedia.org/wiki/Radians Wavelength (λ) = speed of light (

**c**) divided by the frequency (f), where**c**= 299,792,458 meters per ...2 Answers · Science & Mathematics · 17/12/2013

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