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1. ### Probability math question?

Use the binomial probability formula: P(X = k) = C(n,k) * p^k * q^(n-k) n : number of trials (5) k : number...

2 Answers · Science & Mathematics · 12/01/2017

2. ### stats homework -- binomial distribution help?!?

... given by P(K = k) = f(k) = C(n, k) p^k (1 - p)^(n - k), for k in {0, 1, 2... so that P(K = k) = f(k) = C(n, k) p^k q^λ. The three factors...

1 Answers · Education & Reference · 21/06/2012

3. ### Linear Algebra eigenvalue proof question?

Write f(t) = ∑(i = 0, k) c_i t^i Since Av = λv, A^i(v) = A^(i-1)(Av...

1 Answers · Science & Mathematics · 27/11/2013

4. ### looking for books about vampires, nephiliams,and characters in their 20's. i've read twilight, tmi, tid...?

Well, I liked Vampires Rule by K. C. Blake. Don't let the title fool you. It's not really...

6 Answers · Arts & Humanities · 08/09/2011

5. ### The equilibrium constant Kp for the following equilibrium is 37 at 298 K.?

SInce temperature is constant. So, Kc=Kp=37

1 Answers · Science & Mathematics · 17/12/2010

6. ### determine the period ,amplitude and phase shift of f(x)=3cos2(x-pi/4)+1?

y= A cos (θ -d ) K + c A= amplitude , d horizontal shift, c= vertical shift, k = frequency per 2π or 360...

1 Answers · Science & Mathematics · 20/03/2011

7. ### prove nCk = n-2Ck + 2(n-2Ck-1) + n-2Ck-2 Please explain and show all steps. Thanks!?

...be considered a double application of Pascal's rule: C(n,k) = C(n-1,k-1) + C(n-1,k) = C(n-2,k-2) + C(n-2,k-1) + C...

2 Answers · Science & Mathematics · 28/03/2016

8. ### Math question!!!!!!!!!!!!!!!?

... Chris = C So basically: J + K = 19 K + C = 14 J + C = K 1) Use substitution postulate: it means...

1 Answers · Science & Mathematics · 09/02/2009

9. ### 8 Choices, 4 spots = number of options?

Let C(n,k) be the binomial coefficient n!/k!(n-k)! (C(n,k) is the number of ways to select k things from...

1 Answers · Science & Mathematics · 30/07/2009

10. ### CHEMISTRY Equilibriums Problems help PLEASE?

For A+B<-->C+D, K = [C][D]/[A][B]. For completion, the concentrations...

1 Answers · Science & Mathematics · 30/05/2013