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... = (1.124 atm - 0.373 atm) x (2.00 L) / ((0.082057366 L atm/

**K**mol) x (30 + 273)**K**) = 0.0604101 mol CO2 reacted 2. Let...1 Answers · Science & Mathematics · 22/04/2020

...n RT (705/760) (0.195 L) = n (0.08206 Latm/molK)(298

**K**) n = 7.40X10^-3 mol Cl2 7.40X10^-3 mol Cl2 ...1 Answers · Science & Mathematics · 22/04/2020

(349 cm^3) x (2.02 atm / 0.958 atm) x (23 + 273)

**K**/ (31.1 + 273)**K**= 716 cm^33 Answers · Science & Mathematics · 18/04/2020

.... So, Δrxn = -30.5 kJ/mol + 8.314 J/mol (310

**K**) ln (8X10^-4)(5X10^-3)/(5X10^-3) Δrxn = -48.9 ...1 Answers · Science & Mathematics · 16/04/2020

... and L = 334000 J/kg and using

**c**_water = 4186 J/kg·ºC (for which there is...) solve to final temperature T = 47.2ºC = 320**K**3. Because we didn't account for the calorimeter...2 Answers · Science & Mathematics · 14/04/2020

choose #5, which YOU should have realized

1 Answers · Science & Mathematics · 12/04/2020

ΔG° = -R T ln(

**K**) -6.73 = -(8.31 × 10⁻³) × 298 × ln(**K**) ln(**K**) = 2.72**K**= e²˙⁷² Equilibrium constant for the reaction,**K**= 15 The answer: d. 151 Answers · Science & Mathematics · 11/04/2020

...mass we have ½v² = g*14 = 9.8*14 = 137 v² = 274 v = 17 m/s

**c**)**k**= mg / (x - 8) = m*9.8 / 2.3 = 4.26*m If you find this helpful, please select...1 Answers · Science & Mathematics · 11/04/2020

dC/dt = kC so, ∫ (1/

**C**) dC = ∫**k**dt => lnC = kt + lnα i.e. lnC - ln...: if this continued, as t --> ∞ , then**C**(t) --> ∞ Let's hope not!! :)>1 Answers · Science & Mathematics · 07/04/2020

..., from Greek kyklos and in the original it was a hard

**c**(**k**) but given its relationship to a word like circle which comes to...5 Answers · Society & Culture · 08/04/2020

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