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  1. ... = (1.124 atm - 0.373 atm) x (2.00 L) / ((0.082057366 L atm/K mol) x (30 + 273) K) = 0.0604101 mol CO2 reacted 2. Let...

    1 Answers · Science & Mathematics · 22/04/2020

  2. ...n RT (705/760) (0.195 L) = n (0.08206 Latm/molK)(298 K) n = 7.40X10^-3 mol Cl2 7.40X10^-3 mol Cl2 ...

    1 Answers · Science & Mathematics · 22/04/2020

  3. (349 cm^3) x (2.02 atm / 0.958 atm) x (23 + 273) K / (31.1 + 273) K = 716 cm^3

    3 Answers · Science & Mathematics · 18/04/2020

  4. .... So, Δrxn = -30.5 kJ/mol + 8.314 J/mol (310 K) ln (8X10^-4)(5X10^-3)/(5X10^-3) Δrxn = -48.9 ...

    1 Answers · Science & Mathematics · 16/04/2020

  5. ... and L = 334000 J/kg and using c_water = 4186 J/kg·ºC (for which there is...) solve to final temperature T = 47.2ºC = 320 K 3. Because we didn't account for the calorimeter...

    2 Answers · Science & Mathematics · 14/04/2020

  6. ΔG° = -R T ln(K) -6.73 = -(8.31 × 10⁻³) × 298 × ln(K) ln(K) = 2.72 K = e²˙⁷² Equilibrium constant for the reaction, K = 15 The answer: d. 15

    1 Answers · Science & Mathematics · 11/04/2020

  7. ...mass we have ½v² = g*14 = 9.8*14 = 137 v² = 274 v = 17 m/s c) k = mg / (x - 8) = m*9.8 / 2.3 = 4.26*m If you find this helpful, please select...

    1 Answers · Science & Mathematics · 11/04/2020

  8. dC/dt = kC so, ∫ (1/C) dC = ∫ k dt => lnC = kt + lnα  i.e. lnC - ln...: if this continued, as t --> ∞ , then C(t) --> ∞ Let's hope not!! :)>

    1 Answers · Science & Mathematics · 07/04/2020

  9. ..., from Greek kyklos and in the original it was a hard c(k) but given its relationship to a word like circle which comes to...

    5 Answers · Society & Culture · 08/04/2020

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