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  1. ...4e^(-2t) i + 3t² j + 6cos(3t) k v( t ) = -2e^(-2t) i + t^3 j + 2sin(3t) k + C ------> at t = 0 , v = 2j which means <0 , 2 , 0> v( 0...

    2 Answers · Science & Mathematics · 09/09/2011

  2. C(dielectric) = C(air) x K C = Q/V so V(air)/V(dielectric) = K = E(air)/E(dielectric) since E = V/d so you just had it upside down, that's all.

    1 Answers · Science & Mathematics · 17/12/2012

  3. F = k * C[1] * C[2] / r^2 https://en.wikipedia.org/wiki/Coulomb%27s_law...

    2 Answers · Science & Mathematics · 14/02/2019

  4. K = C + 273 K = 6C + 33 6C + 33 = C + 273 5C = 240 C = 240/5 = 48

    2 Answers · Science & Mathematics · 13/08/2007

  5. K = °C+273.15, but rewritting the equation to get Kelvin we obtain: KC+273 So the answer is 323 K.

    4 Answers · Science & Mathematics · 26/01/2009

  6. K= C + 273 to convert F to K -> [(F-32) / (1.8)] + 273

    3 Answers · Science & Mathematics · 09/07/2011

  7. a) 303.15K b) 273.15K c) 773.15K d) -273.15C e) K = C + 273.15

    3 Answers · Science & Mathematics · 08/01/2008

  8. c_ice = 2.05 J/g.K c_water = 4.18 J/g.K c_steam = 2.08 J/g.K Hfus...

    1 Answers · Science & Mathematics · 22/09/2011

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