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1. ### How i can find X? (V*K*C)/F =(1+E)*(ln 1/1-X)-E*X?

First off, note that ln(1) is an actual constant and simplifies to 0. The problem is now reduced to (VKC)/F=(1+E)*0-EX So now, you have a variable multiplied by X. To get rid of it, you want to divide both...

2 Answers · Science & Mathematics · 12/07/2009

2. ### Who will answer it first?You! O.K c'MON?

Firstly, solving the original equation. x/3 = y + 2/3. Multiplying everything by 3 leaves x = 3y + 2. Now that we have an equation for x, we can solve the expression (x + 7)/3. Using the formula for x above, x + 7 = (3y + 2) + 7 = 3y + 9. Then, (x + 7)/3 = (3y + 9)/3 = y + 3...

5 Answers · Science & Mathematics · 24/06/2010

3. ### k=c+273, for c solve the variable?

c=K-273

3 Answers · Science & Mathematics · 26/05/2008

4. ### Given a =2i -4j-k c=3i + j -2k find (a.c) (axc) ?

I am assuming that i,j,k represent a 3 d system and therefore a and b are vectors a = {2, -4, -1}; c = {3, 1, -2}; and a.c is the Dot Product then a.c = 4

2 Answers · Science & Mathematics · 11/11/2013

5. ### How do I Solve for k C= k over m( 1 – k) ?

C = k / (m(1 - k)) cross multiply Cm(1 - k) = k distribute LHS Cm - Cmk = k add Cmk to both sides Cm = k + Cmk factor Cm = k(1 + Cm) divide both sides by (1 + Cm) Cm / (1 + Cm) = k...

3 Answers · Science & Mathematics · 26/08/2008

6. ### Solve: y'' + y = 0, Answer: K sin[t] + C cos[t], where K & C are constants, Why? Thanks for Any Help =)!?

Note that the characteristic of this equation is: y^2 + 1 = 0. This solves to yield y = ±i and the solutions would be: y = K*sin(t) + C*cos(t), for some constants K and C. I hope this helps!

4 Answers · Science & Mathematics · 31/03/2011

7. ### What is the amp, k, c, and period of the function? 10 points!?

y=6-2sin1/2(x+45) distribute the 1/2 y=6-2sin[x/2-22.5)

1 Answers · Science & Mathematics · 15/07/2010

8. ### For y= k+(c/x+b), state the equation of the vertical and horizontal asymptotes?

Suppose that you know that m = 2 and c = 3. You need to examine the x- and y- asymptotes. There is no way that x could equal 0 in this equation because any number divided by 0 is undefined, so if you were to substitute 0 for x in the equation you would get y...

3 Answers · Science & Mathematics · 24/08/2008

9. ### Let F=(9yz)i+(5xz)j+(6xy)k. Warm up by computing the following: A. div F= B. curl F= i+ j+ k C. div curl?

A) div F = (∂/∂x)(9yz) + (∂/∂y)(5xz) + (∂/∂z)(6xy) = 0. B) curl F = |..i.......j.......k...| |∂/∂x..∂/∂y..∂/∂z| = (x) i + (3y) j + (-4z) k. |9yz...5xz...6xy| C) Using part B, div(curl F) = (∂/∂x)(x) + (∂/∂y)(3y) + (∂/∂z)(-4z) = 0...

1 Answers · Science & Mathematics · 09/12/2013

10. ### Consider F and C defined below. F(x,y,z) = x2y i + (1/3)x3 j + xy k C is the curve of intersection of the hype?

Note that curl F = <x, -y, 0>. Moreover, let S be the surface inside C. So, ∫c F · dr = ∫∫s curl F · dS, by Stokes' Theorem = ∫∫ <x, -y, 0> · <-(-2x), -(2y), 1>...

1 Answers · Science & Mathematics · 09/05/2011